USEFUL HACMP COMMANDS
clstat - show cluster state and substate; needs clinfo.
cldump - SNMP-based tool to show cluster state
cldisp - similar to cldump, perl script to show cluster state.
cltopinfo - list the local view of the cluster topology.
clshowsrv -a - list the local view of the cluster subsystems.
clfindres (-s) - locate the resource groups and display status.
clRGinfo -v - locate the resource groups and display status.
clcycle - rotate some of the log files.
cl_ping - a cluster ping program with more arguments.
clrsh - cluster rsh program that take cluster node names as argument.
clgetactivenodes - which nodes are active?
get_local_nodename - what is the name of the local node?
clconfig - check the HACMP ODM.
clRGmove - online/offline or move resource groups.
cldare - sync/fix the cluster.
cllsgrp - list the resource groups.
clsnapshotinfo - create a large snapshot of the hacmp configuration.
cllscf - list the network configuration of an hacmp cluster.
clshowres - show the resource group configuration.
cllsif - show network interface information.
cllsres - show short resource group information.
lssrc -ls clstrmgrES - list the cluster manager state.
lssrc -ls topsvcs - show heartbeat information.
cllsnode - list a node centric overview of the hacmp configuration.
AIX is short for Advanced Interactive eXecutive. AIX is the UNIX operating system from IBM for RS/6000, pSeries and the latest p5 & p5+ systems. Currently, it is called "System P". AIX/5L the 5L addition to AIX stands for version 5 and Linux affinity. AIX and RS/6000 was released on the 14th of February, 1990 in London. Currently, the latest release of AIX is version 6. AIX 7 beta will be released in Aug 2010, along with the new POWER7 hardware range.
Tanti Technology
- sandeep tanti
- Bangalore, karnataka, India
- Multi-platform UNIX systems consultant and administrator in mutualized and virtualized environments I have 4.5+ years experience in AIX system Administration field. This site will be helpful for system administrator in their day to day activities.Your comments on posts are welcome.This blog is all about IBM AIX Unix flavour. This blog will be used by System admins who will be using AIX in their work life. It can also be used for those newbies who want to get certifications in AIX Administration. This blog will be updated frequently to help the system admins and other new learners. DISCLAIMER: Please note that blog owner takes no responsibility of any kind for any type of data loss or damage by trying any of the command/method mentioned in this blog. You may use the commands/method/scripts on your own responsibility. If you find something useful, a comment would be appreciated to let other viewers also know that the solution/method work(ed) for you.
Monday, 4 July 2011
TESTING HACMP: HA FAILOVER SCENARIOS
TESTING HACMP: HA FAILOVER SCENARIOS
1. Graceful
For graceful failover, you can run “smitty clstop” then select graceful option. This will not change
anything except stopping the cluster on that node.
Note: If you stop the cluster, check the status using lssrc –g cluster, sometimes clstrmgrES daemon will
take long time to stop, DO NOT KILL THIS DAEMON.It will stop automatically after a while.
You can do this on both the nodes
2. Takeover
For takeover, run “smitty clstop” with takeover option, this will stop the cluster on that node and the
standby node will take over the pakage
You can do this on both the nodes
3. Soft Pakckage Failover
Run smitty cm_hacmp_resource_group_and_application_management_menu >>>Move a
Resource Group to Another Node >>>>select the package name and node name
>>>enter
This will move the package from that node to the node that you have selected in the above menu. This
method will give lot of troubles in HA 4.5 whereas it runs good on HA 5.2 unless we have any apps
startup issues.
You can do this on both the nodes
4. Failover Network Adapter(s):
For this type of testing , run “ifconfig enx down” , then package IP will failover to primary adapter. You
can not even see any outage or anything.
We can manually (ifconfig enx up) bring it back to original adapter , but better to reboot the server to
bring the package back to the original node
5. Hardware Failure (crash):
This is a standard type of testing; run the command “reboot –q” then the node will godown without
stopping any apps and come up immediately. The package will failover to the standby node with in 2
min os downtime (Even tough HA failover is fast, some apps will take long time to start
1. Graceful
For graceful failover, you can run “smitty clstop” then select graceful option. This will not change
anything except stopping the cluster on that node.
Note: If you stop the cluster, check the status using lssrc –g cluster, sometimes clstrmgrES daemon will
take long time to stop, DO NOT KILL THIS DAEMON.It will stop automatically after a while.
You can do this on both the nodes
2. Takeover
For takeover, run “smitty clstop” with takeover option, this will stop the cluster on that node and the
standby node will take over the pakage
You can do this on both the nodes
3. Soft Pakckage Failover
Run smitty cm_hacmp_resource_group_and_application_management_menu >>>Move a
Resource Group to Another Node >>>>select the package name and node name
>>>enter
This will move the package from that node to the node that you have selected in the above menu. This
method will give lot of troubles in HA 4.5 whereas it runs good on HA 5.2 unless we have any apps
startup issues.
You can do this on both the nodes
4. Failover Network Adapter(s):
For this type of testing , run “ifconfig enx down” , then package IP will failover to primary adapter. You
can not even see any outage or anything.
We can manually (ifconfig enx up) bring it back to original adapter , but better to reboot the server to
bring the package back to the original node
5. Hardware Failure (crash):
This is a standard type of testing; run the command “reboot –q” then the node will godown without
stopping any apps and come up immediately. The package will failover to the standby node with in 2
min os downtime (Even tough HA failover is fast, some apps will take long time to start
STEPS TO CONFIGURE HACMP:
STEPS TO CONFIGURE HACMP:
1. Install the nodes, make sure the redundancy is maintained for power supplies, n/w and
fiber n/ws. Then Install AIX on the nodes.
2. Install all the HACMP filesets except HAview and HATivoli.
Install all the RSCT filesets from the AIX base CD.
Make sure that the AIX, HACMP patches and server code are at the latest level (ideally
recommended).
4. Check for fileset bos.clvm to be present on both the nodes. This is required to make the
VGs enhanced concurrent capable.
5. V.IMP: Reboot both the nodes after installing the HACMP filesets.
6. Configure shared storage on both the nodes. Also in case of a disk heartbeat, assign a
1GB shared storage LUN on both nodes.
7. Create the required VGs only on the first node. The VGs can be either normal VGs or
Enhanced concurrent VGs. Assign particular major number to each VGs while creating
the VGs. Record the major no. information.
To check the Majar no. use the command:
ls –lrt /dev grep
Mount automatically at system restart should be set to NO.
8. Varyon the VGs that was just created.
9. V.IMP: Create log LV on each VG first before creating any new LV. Give a unique
name to logLV.
Destroy the content of logLV by: logform /dev/loglvname
Repeat this step for all VGs that were created.
10. Create all the necessary LVs on each VG.
11. Create all the necessary file systems on each LV created…..you can create mount pts
as per the requirement of the customer,
Mount automatically at system restart should be set to NO.
12. umount all the filesystems and varyoff all the VGs.
13. chvg –an All VGs will be set to do not mount automatically at
System restart.
14. Go to node 2 and run cfgmgr –v to import the shared volumes.
15. Import all the VGs on node 2
use smitty importvg import with the same major number as assigned on node
16. Run chvg –an for all VGs on node 2.
17. V.IMP: Identify the boot1, boot2, service ip and persistent ip for both the nodes and make the entry
in the /etc/hosts.
18. Define cluster name.
19. Define the cluster nodes. #smitty hacmp -> Extended Configuration -> Extended topology
configuration -> Configure an HACMP node - > Add a node to an HACMP cluster Define both the
nodes on after the other.
20. Discover HACMP config: This will import for both nodes all the node info, boot ips,
service ips from the /etc/hosts
smitty hacmp -> Extended configurations -> Discover hacmp related information
Step21 Adding Communication interface
Add HACMP communication interfaces. (Ether interfaces.)
smitty hacmp -> Extended Configuration -> Extended Topology Configuration ->
Configure HACMP networks -> Add a network to the HACMP cluster.
Select ether and Press enter.
Then select diskhb and Press enter. Diskhb is your non-tcpip heartbeat.
step 22 Adding device for Disk Heart Beat
Include the interfaces/devices in the ether n/w and diskhb already defined.
smitty hacmp -> Extended Configuration -> Extended Topology Configuration ->
Configure HACMP communication interfaces/devices -> Add communication Interfaces/devices.
step23 Adding boot IP & Disk heart beat information
Include all the four boot ips (2 for each nodes) in this ether interface already defined.Then include the
disk for heartbeat on both the nodes in the diskhb already defined
step 24 Adding persistent IP
Add the persistent IPs:
smitty hacmp -> Extended Configuration -> Extended Topology Configuration ->
Configure HACMP persistent nodes IP label/Addresses
step 25 Adding Persistent IP labels
Add a persistent ip label for both nodes.
step 26 Defining IP labels
Define the service IP labels for both nodes.
smitty hacmp -> Extended Configuration -> Extended Resource Configuration ->
HACMP extended resource configuration -> Configure HACMP service IP label
step 27 Adding Resource Group
Add Resource Groups:
smitty hacmp -> Extended Configuration -> Extended Resource Configuration ->
HACMP extended resource group configuration
Continue similarly for all the resource groups.
The node selected first while defining the resource group will be the primary owner of
that resource group. The node after that is secondary node.
Make sure you set primary node correctly for each resource group. Also set the failover/fallback policies
as per the requirement of the setup
step 28 Setting attributes of Resource group
Set attributes of the resource groups already defined:
Here you have to actually assign the resources to the resource groups.
smitty hacmp -> Extended Configuration -> Extended Resource Configuration ->
HACMP extended resource group configuration
step 29 Adding IP label & RG owned by Node
Add the service IP label for the owner node and also the VGs owned by the owner node
Of this resource group.
step 30 & 31 Synchronize & start Cluster
Synchronize the cluster:
This will sync the info from one node to second node.
Smitty cl_sync
That’s it. Now you are ready to start the cluster.
Smitty clstart
You can start the cluster together on both nodes or start individually on each node.
You can start the cluster together on both nodes or start individually on each node.
Step 32 & 33 Check for cluster Stabilize & VG varied on
Wait for the cluster to stabilize. You can check when the cluster is up by following
commands
a. netstat –i
b. ifconfig –a : look-out for service ip. It will show on each node if the cluster is up.
Check whether the VGs under cluster’s RGs are varied-ON and the filesystems in the
VGs are mounted after the cluster start.
Here test1vg and test2vg are VGs which are varied-ON when the cluster is started and
Filesystems /test2 and /test3 are mounted when the cluster starts.
/test2 and /test3 are in test2vg which is part of the RG which is owned by this node.
32. Perform all the tests such as resource take-over, node failure, n/w failure and verify
the cluster before releasing the system to the customer.
Specifying the default gateway on a specific interface
When you're using HACMP, you usually have multiple network adapters installed and thus multiple
network interface to handle with. If AIX configured the default gateway on a wrong interface (like on
your management interface instead of the boot interface), you might want to change this, so network
traffic isn't sent over the management interface. Here's how you can do this:
First, stop HACMP or do a take-over of the resource groups to another node; this will avoid any
problems with applications when you start fiddling with the network configuration.
Then open up a virtual terminal window to the host on your HMC. Otherwise you would loose the
connection, as soon as you drop the current default gateway.
Now you need to determine where your current default gateway is configured. You can do this by
typing: lsattr -El inet0 and netstat -nr. The lsattr command will show you the current default gateway
route and the netstat command will show you the interface it is configured on. You can also check the
ODM: odmget -q"attribute=route" CuAt.
Now, delete the default gateway like this:
lsattr -El inet0 | awk '$2 ~ /hopcount/ { print $2 }' | read GW
chdev -l inet0 -a delroute=${GW}
If you would now use the route command to specifiy the default gateway on a specific interface, like
this:
route add 0 [ip address of default gateway: xxx.xxx.xxx.254] -if enX
You will have a working entry for the default gateway. But... the route command does not change
anything in the ODM. As soon as your system reboots; the default gateway is gone again. Not a good
idea.
A better solution is to use the chdev command:
chdev -l inet0 -a addroute=net,-hopcount,0,,0,[ip address of default gateway]
This will set the default gateway to the first interface available.
To specify the interface use:
chdev -l inet0 -a addroute=net,-hopcount,0,if,enX,,0,[ip address of default gateway]
Substitute the correct interface for enX in the command above.
If you previously used the route add command, and after that you use chdev to enter the default
gateway, then this will fail. You have to delete it first by using route delete 0, and then give the chdev
command.
Afterwards, check with lsattr -El inet0 and odmget -q"attribute=route" CuAt if the new default gateway
is properly configured. And ofcourse, try to ping the IP address of the default gateway and some outside
address. Now reboot your system and check if the default gateway remains configured on the correct
interface. And startup HACMP again!
1. Install the nodes, make sure the redundancy is maintained for power supplies, n/w and
fiber n/ws. Then Install AIX on the nodes.
2. Install all the HACMP filesets except HAview and HATivoli.
Install all the RSCT filesets from the AIX base CD.
Make sure that the AIX, HACMP patches and server code are at the latest level (ideally
recommended).
4. Check for fileset bos.clvm to be present on both the nodes. This is required to make the
VGs enhanced concurrent capable.
5. V.IMP: Reboot both the nodes after installing the HACMP filesets.
6. Configure shared storage on both the nodes. Also in case of a disk heartbeat, assign a
1GB shared storage LUN on both nodes.
7. Create the required VGs only on the first node. The VGs can be either normal VGs or
Enhanced concurrent VGs. Assign particular major number to each VGs while creating
the VGs. Record the major no. information.
To check the Majar no. use the command:
ls –lrt /dev grep
Mount automatically at system restart should be set to NO.
8. Varyon the VGs that was just created.
9. V.IMP: Create log LV on each VG first before creating any new LV. Give a unique
name to logLV.
Destroy the content of logLV by: logform /dev/loglvname
Repeat this step for all VGs that were created.
10. Create all the necessary LVs on each VG.
11. Create all the necessary file systems on each LV created…..you can create mount pts
as per the requirement of the customer,
Mount automatically at system restart should be set to NO.
12. umount all the filesystems and varyoff all the VGs.
13. chvg –an All VGs will be set to do not mount automatically at
System restart.
14. Go to node 2 and run cfgmgr –v to import the shared volumes.
15. Import all the VGs on node 2
use smitty importvg import with the same major number as assigned on node
16. Run chvg –an for all VGs on node 2.
17. V.IMP: Identify the boot1, boot2, service ip and persistent ip for both the nodes and make the entry
in the /etc/hosts.
18. Define cluster name.
19. Define the cluster nodes. #smitty hacmp -> Extended Configuration -> Extended topology
configuration -> Configure an HACMP node - > Add a node to an HACMP cluster Define both the
nodes on after the other.
20. Discover HACMP config: This will import for both nodes all the node info, boot ips,
service ips from the /etc/hosts
smitty hacmp -> Extended configurations -> Discover hacmp related information
Step21 Adding Communication interface
Add HACMP communication interfaces. (Ether interfaces.)
smitty hacmp -> Extended Configuration -> Extended Topology Configuration ->
Configure HACMP networks -> Add a network to the HACMP cluster.
Select ether and Press enter.
Then select diskhb and Press enter. Diskhb is your non-tcpip heartbeat.
step 22 Adding device for Disk Heart Beat
Include the interfaces/devices in the ether n/w and diskhb already defined.
smitty hacmp -> Extended Configuration -> Extended Topology Configuration ->
Configure HACMP communication interfaces/devices -> Add communication Interfaces/devices.
step23 Adding boot IP & Disk heart beat information
Include all the four boot ips (2 for each nodes) in this ether interface already defined.Then include the
disk for heartbeat on both the nodes in the diskhb already defined
step 24 Adding persistent IP
Add the persistent IPs:
smitty hacmp -> Extended Configuration -> Extended Topology Configuration ->
Configure HACMP persistent nodes IP label/Addresses
step 25 Adding Persistent IP labels
Add a persistent ip label for both nodes.
step 26 Defining IP labels
Define the service IP labels for both nodes.
smitty hacmp -> Extended Configuration -> Extended Resource Configuration ->
HACMP extended resource configuration -> Configure HACMP service IP label
step 27 Adding Resource Group
Add Resource Groups:
smitty hacmp -> Extended Configuration -> Extended Resource Configuration ->
HACMP extended resource group configuration
Continue similarly for all the resource groups.
The node selected first while defining the resource group will be the primary owner of
that resource group. The node after that is secondary node.
Make sure you set primary node correctly for each resource group. Also set the failover/fallback policies
as per the requirement of the setup
step 28 Setting attributes of Resource group
Set attributes of the resource groups already defined:
Here you have to actually assign the resources to the resource groups.
smitty hacmp -> Extended Configuration -> Extended Resource Configuration ->
HACMP extended resource group configuration
step 29 Adding IP label & RG owned by Node
Add the service IP label for the owner node and also the VGs owned by the owner node
Of this resource group.
step 30 & 31 Synchronize & start Cluster
Synchronize the cluster:
This will sync the info from one node to second node.
Smitty cl_sync
That’s it. Now you are ready to start the cluster.
Smitty clstart
You can start the cluster together on both nodes or start individually on each node.
You can start the cluster together on both nodes or start individually on each node.
Step 32 & 33 Check for cluster Stabilize & VG varied on
Wait for the cluster to stabilize. You can check when the cluster is up by following
commands
a. netstat –i
b. ifconfig –a : look-out for service ip. It will show on each node if the cluster is up.
Check whether the VGs under cluster’s RGs are varied-ON and the filesystems in the
VGs are mounted after the cluster start.
Here test1vg and test2vg are VGs which are varied-ON when the cluster is started and
Filesystems /test2 and /test3 are mounted when the cluster starts.
/test2 and /test3 are in test2vg which is part of the RG which is owned by this node.
32. Perform all the tests such as resource take-over, node failure, n/w failure and verify
the cluster before releasing the system to the customer.
Specifying the default gateway on a specific interface
When you're using HACMP, you usually have multiple network adapters installed and thus multiple
network interface to handle with. If AIX configured the default gateway on a wrong interface (like on
your management interface instead of the boot interface), you might want to change this, so network
traffic isn't sent over the management interface. Here's how you can do this:
First, stop HACMP or do a take-over of the resource groups to another node; this will avoid any
problems with applications when you start fiddling with the network configuration.
Then open up a virtual terminal window to the host on your HMC. Otherwise you would loose the
connection, as soon as you drop the current default gateway.
Now you need to determine where your current default gateway is configured. You can do this by
typing: lsattr -El inet0 and netstat -nr. The lsattr command will show you the current default gateway
route and the netstat command will show you the interface it is configured on. You can also check the
ODM: odmget -q"attribute=route" CuAt.
Now, delete the default gateway like this:
lsattr -El inet0 | awk '$2 ~ /hopcount/ { print $2 }' | read GW
chdev -l inet0 -a delroute=${GW}
If you would now use the route command to specifiy the default gateway on a specific interface, like
this:
route add 0 [ip address of default gateway: xxx.xxx.xxx.254] -if enX
You will have a working entry for the default gateway. But... the route command does not change
anything in the ODM. As soon as your system reboots; the default gateway is gone again. Not a good
idea.
A better solution is to use the chdev command:
chdev -l inet0 -a addroute=net,-hopcount,0,,0,[ip address of default gateway]
This will set the default gateway to the first interface available.
To specify the interface use:
chdev -l inet0 -a addroute=net,-hopcount,0,if,enX,,0,[ip address of default gateway]
Substitute the correct interface for enX in the command above.
If you previously used the route add command, and after that you use chdev to enter the default
gateway, then this will fail. You have to delete it first by using route delete 0, and then give the chdev
command.
Afterwards, check with lsattr -El inet0 and odmget -q"attribute=route" CuAt if the new default gateway
is properly configured. And ofcourse, try to ping the IP address of the default gateway and some outside
address. Now reboot your system and check if the default gateway remains configured on the correct
interface. And startup HACMP again!
HACMP V5.X DISK HEARTBEAT DEVICE CONFIGURATION
HACMP V5.X DISK HEARTBEAT DEVICE CONFIGURATION
Introduction
This document is intended to supplement existing documentation on how to configure, test, and
monitor a disk heartbeat device and network in HACMP/ES V 5.x. This feature is new in V5.1, and it
provides another alternative for non-ip based heartbeats. The intent of this document is to provide stepby-
step directions as they are currently sketchy in the HACMP v5.1 pubs. This will hopefully clarify
several misconceptions that have been brought to my attention.
This example consists of a two-node cluster (nodes GT40 & SL55) with shared ESS vpath devices. If
more than two nodes exist in your cluster, you will need N number or non-ip heartbeat networks.
Where N represents the number of nodes in the cluster. (i.e. three node cluster requires 3 non-ip
heartbeat networks). This creates a heartbeat ring.
It’s worth noting that one should not confuse concurrent volume groups with concurrent resource
groups. And note, there is a difference between concurrent volume groups and enhanced concurrent
volume groups. A concurrent resource group is one which may be active on more than one node at a
type. A concurrent volume group also shares the characteristic that it may be active on more than one
node at a time. This is also true for an enhanced concurrent VG; however, in a non-concurrent resource
group, the enhanced concurrent VG, while it may be active and not have a SCSI reserve residing on the
disk, it’s data is only normally accessed by one system at a time.
Pre-Reqs
In this document, it is assumed that the shared storage devices are already made available and
configured to AIX, and that the proper levels of RSCT and HACMP are already installed. Since utilizing
enhanced-concurrent volume groups, it is also necessary to make sure that bos.clvm.enh is installed.
This is not normally installed as part of a HACMP installation via the installp command.
Disk Heartbeat Details
This provides the ability to use existing shared disks, regardless of disk type, to provide a serial network
like heartbeat path. A benefit of this is that one need not dedicate the integrated serial ports for HACMP
heartbeats (if supported on the subject systems) or purchase an 8-port asynchronous adapter.
This feature utilizes a special area on the disk previously reserved for “Concurrent Capable” volume
groups (traditionally only for SSA disks). Since AIX 5.2 dropped support for the SSA concurrent volume
groups, this fit makes it available for use. This also means that the disk chosen for serial heartbeat can
be part of a data volume group. (Note Performance Concerns below)
The disk heart beating code went into the 2.2.1.30 version of RSCT. Some recommended APARs bring
that to 2.2.1.31. If you've got that level installed, and HACMP 5.1, you can use disk heart beating. The
relevant file to look for is /usr/sbin/rsct/bin/hats_diskhb_nim. Though it is supported mainly through
RSCT, we recommend AIX 5.2 when utilizing disk heartbeat.
To use disk heartbeats, no node can issue a SCSI reserve for the disk. This is because both nodes using it
for heart beating must be able to read and write to that disk. It is sufficient that the disk be in an
enhanced concurrent volume group to meet this requirement. (It should also be possible to use a disk
that is in no volume group for disk heart beating. RSCT certainly won't care; but HACMP SMIT panels
may not be particularly helpful in setting this up.)
Now, in HACMP 5.1 with AIX 5.1, enhanced concurrent mode volume groups can be used only in
concurrent (or "online on all available nodes") resource groups. This means that disk heart beating is
useful only to people running concurrent configurations, or who can allocate such a volume group/disk
(which is certainly possible, though perhaps an expensive approach). In other words, at HACMP 5.1 and
AIX 5.1, typical HACMP clusters (with a server and idle standby) will require an additional concurrent
resource group with a disk in an enhanced concurrent VG dedicated for heartbeat use. At AIX 5.2, disk
heartbeats can exist on an enhanced concurrent VG that resides in a non-concurrent resource group. At
AIX 5.2, one may also use the fast disk takeover feature in non-concurrent resource groups with
enhanced concurrent volume groups. With HACMP 5.1 and AIX 5.2, enhanced concurrent mode volume
groups can be used in serial access configurations for fast disk takeover, along with disk heart beating.
(AIX 5.2 requires RSCT 2.3.1.0 or later) That is, the facility becomes usable to the average customer,
without committment of additional resource, since disk heart beating can occur on a volume group used
for ordinary filesystem and logical volume activity.
Performance Concerns with Disk Heart Beating
Most modern disks take somewhere around 15 milliseconds to service an IO request, which means that
they can't do much more than 60 seeks per second. The sectors used for disk heart beating are part of
the VGDA, which is at the outer edge of the disk, and may not be near the application data. This means
that every time a disk heart beat is done, a seek will have to be done. Disk heart beating will typically
(with the default parameters) require four (4) seeks per second. That is each of two nodes will write to
the disk and read from the disk once/second, for a total of 4 IOPS. So, if possible, a disk should be
selected as a heart beat path that does not normally do more than about 50 seeks per second. The
filemon tool can be used to monitor the seek activity on a disk.
In cases where a disk must be used for heart beating that already has a high seek rate, it may be
necessary to change the heart beat timing parameters to prevent long write delays from being seen as a
failure.
The above cautions as stated apply to JBOD configurations, and should be modified based on the
technology of the disk subsystem:
• If the disk used for heart beating is in a controller that provides large amounts of cache - such as the
ESS - the number of seeks per second can be much larger
• If the disk used for heart beating is part of a RAID set without a caching front end controller, the disk
may be able to support fewer seeks, due to the extra activity required by RAID operations
Pros & Cons of using Disk Heart Beating
Pros:
1. No additional hardware needed.
2. Easier to span greater distances.
3. No loss in usable storage space and can use existing data volume groups.
4. Uses enhanced concurrent vgs which also allows for fast-disk takeover.
Cons:
1. Must be aware of the devices diskhb uses and administer devices properly*
2. Lose the forced down option of stopping cluster services because of enhanced concurrent vg usage.
*I have had a customer delete all their disk definitions and run cfgmgr again to clean up number holes in
their device definition list. When they did, obviously , the device names did not come back in the same
order as they were before. So the diskhb device assigned to HACMP, was no longer valid as a different
device was configured using the old device name and it was not part of an enhanced concurrent vg.
Hence diskhb no longer worked, and since the customer did not monitor their cluster either, they were
unaware that the diskhb no longer worked.
Configuring Disk Heartbeat
As mentioned previously, disk heartbeat utilizes enhanced-concurrent volume groups. If starting with a
new configuration of disks, you will want to create enhanced-concurrent volume groups, either
manually, or by utilizing C-SPOC. My example shows using C-SPOC which is the best practice to use here.
If you plan to use an existing volume group for disk heartbeats that is not enhanced concurrent, then
you will have to convert them to such using the chvg command. We recommend that the VG be active
on only one node, and that the application not be running when making this change run chvg –C vgname
to change the VG to enhanced concurrent mode. Vary it off, then run importvg –L vgname on the other
node to make it aware that the vg is now enhanced concurrent capable. If using this method, you can
skip to the “Creating Disk Heartbeat Devices and Network” section of this document.
Disk and VG Preparation
To be able to use C-SPOC successfully, it is required that some basic IP based topology already exists,
and that the storage devices have their PVIDs in both system’s ODMs. This can be verified by running
lspv on each system. If a PVID does not exist on each system, it is necessary to run chdev -l -a pv=yes on
each system. This will allow C-SPOC to match up the device(s) as known shared storage devices.
In this example, vpath0 on GT40 is the same virtual disk as vpath3 on SL55.
Use C-SPOC to create an Enhanced Concurrent volume group. In the following example, since vpath
devices are being used, the following smit screen paths were used.
Go to HACMP Concurrent Logical Volume smitty cl_admin Create a Concurrent Volume Group with
Data Concurrent Volume Groups Management Path Devices and press Enter
Choose the appropriate nodes, and then choose the appropriate shared storage devices based on pvids
(vpath0 and vpath3 in this example). Choose a name for the VG , desired PP size, make sure that
Enhanced Concurrent Mode is set to true and press Enter. (enhconcvg in this example). This will create
the shared enhanced-concurrent vg needed for our disk heartbeat. .
It’s a good idea to verify via lspv once this has completed to make sure the device and vg is show
appropriately as follows:
GT40#/ lspv
vpath0 000a7f5af78e0cf4 enhconcvg
SL55#/lspv
vpath3 000a7f5af78e0cf4 enhconcvg
Creating Disk Heartbeat Devices and Network
There are two different ways to do this. Since we have already created the enhanced concurrent vg, we
can use the discovery method (1) and let HA find it for us. Or we can do this manually via the Predefined
devices method (2). Following is an example of each.
1) Creating via Discover Method: (See Note)
Extended Enter smitty hacmp Press Discover HACMP-related Information from Configured
Nodes Configuration Enter
This will run automatically and create a clip_config file that contains the information it has discovered.
Once completed, go back to the Extended Configuration menu and chose:
Extended Topology Add Communication Configure HACMP Communication
Interfaces/Devices Configuration Add Discovered Communication Interface and Interfaces/Devices
Choose appropriate devices (ex. vpath0 and Communication Devices Devices vpath3)
Select Point-to-Point Pair of Discovered Communication Devices to Add
Move cursor to desired item and press F7. Use arrow keys to scroll.
ONE OR MORE items can be selected.
Press Enter AFTER making all selections.
# Node Device Device Path Pvid
> nodeGT40 vpath0 /dev/vpath0 000a7f5af78
> nodeSL55 vpath3 /dev/vpath3 000a7f5af78
Note: Base HA 5.1 appears to have a problem when using the Discovered Devices this method. If you get
this error: "ERROR: Invalid node name 000a7f5af78e0cf4".
Then you will need apar IY51594. Otherwise you will have to create via the Pre-Defined Devices method.
Once corrected, this section will be completed
2) Creating via Pre-Defined Devices Method
When using this method, it is necessary to create a diskhb network first, then assign the disk-node pair
devices to the network. Create the diskhb network as follows:
Extended Topology Extended Configuration smitty hacmp Add a Network to the HACMP cluster
Configure HACMP Networks Configuration Enter desired network name (ex. disknet1)—press choose
diskhb Enter
Extended Topology Extended Configuration smitty hacmp Add Configure HACMP Communication
Interfaces/Devices Configuration Add Pre-Defined Communication Interfaces and Communication
Interfaces/Devices Devices
Choose your diskhb Network Name Communication Devices
Add a Communication Device
Type or select values in entry fields.
Press Enter AFTER making all desired changes.
[Entry Fields]
* Device Name [GT40_hboverdisk]
* Network Type diskhb
* Network Name disknet1
* Device Path [/dev/vpath0]
* Node Name [GT40]
For Device Name, that is a unique name you can chose. It will show up in your topology under this
name, much like serial heartbeat and ttys have in the past.
For the Device Path, you want to put in /dev/. Then choose the corresponding node for this device and
device name (ex. GT40). Then press Enter.
You will repeat this process for the other node (ex. SL55) and the other device (vpath3). This will
complete both devices for the diskhb network.
Testing Disk Heartbeat Connectivity
Once the device and network definitions have been created, it is a good idea to test it and make sure
communications is working properly. If the volume group is varied on in normal mode on one of the
nodes, the test will probably not work.
/usr/sbin/rsct/bin/dhb_read is used to test the validity of a diskhb connection. The usage of dhb_read is
as follows:
dhb_read -p devicename //dump diskhb sector contents
dhb_read -p devicename -r //receive data over diskhb network
dhb_read -p devicename -t //transmit data over diskhb network
To test that disknet1, in the example configuration, can communicate from nodeB(ex. SL55) to nodeA
(ex. GT40), you would run the following commands:
On nodeA, enter:
dhb_read -p rvpath0 -r
On nodeB, enter:
dhb_read -p rvpath3 -t
Note: That the device name is raw device as designated with the “r” proceeding the device name.
If the link from nodeB to nodeA is operational, both nodes will display:
Link operating normally.
You can run this again and swap which node transmits and which one receives. To make the network
active, it is necessary to sync up the cluster. Since the volume group has not been added to the resource
group, we will sync up once instead of twice.
Add Shared Disk as a Shared Resource
In most cases you would have your diskhb device on a shared data vg. It is necessary to add that vg into
your resource group and synchronize the cluster.
Extended Extended Configuration smitty hacmp Resource Configuration >
Change/Show Extended Resource Group Configuration and press Enter. Resources and Attributes for a
Resource Group
Choose the appropriate resource group, enter the new vg (enhconcvg) into the volume group list and
press Enter.
Return to the top of the Extended Configuration menu and synchronize the cluster.
Monitor Disk Heartbeat
Once the cluster is up and running, you can monitor the activity of the disk (actually all) heartbeats via
lssrc -ls topsvcs. An example of the output follows:
Subsystem Group PID Status
topsvcs topsvcs 32108 active
Network Name Indx Defd Mbrs St Adapter ID Group ID
disknet1 [ 3] 2 2 S 255.255.10.0 255.255.10.1
disknet1 [ 3] rvpath3 0x86cd1b02 0x86cd1b4f
HB Interval = 2 secs. Sensitivity = 4 missed beats
Missed HBs: Total: 0 Current group: 0
Packets sent : 229 ICMP 0 Errors: 0 No mbuf: 0
Packets received: 217 ICMP 0 Dropped: 0
NIM's PID: 28724
Be aware that there is a grace period for heartbeats to start processing. This is normally around 60
seconds. So if you run this command quickly after starting the cluster, you may not see anything at all
until heartbeat processing is started after the grace period time has elapsed.
Introduction
This document is intended to supplement existing documentation on how to configure, test, and
monitor a disk heartbeat device and network in HACMP/ES V 5.x. This feature is new in V5.1, and it
provides another alternative for non-ip based heartbeats. The intent of this document is to provide stepby-
step directions as they are currently sketchy in the HACMP v5.1 pubs. This will hopefully clarify
several misconceptions that have been brought to my attention.
This example consists of a two-node cluster (nodes GT40 & SL55) with shared ESS vpath devices. If
more than two nodes exist in your cluster, you will need N number or non-ip heartbeat networks.
Where N represents the number of nodes in the cluster. (i.e. three node cluster requires 3 non-ip
heartbeat networks). This creates a heartbeat ring.
It’s worth noting that one should not confuse concurrent volume groups with concurrent resource
groups. And note, there is a difference between concurrent volume groups and enhanced concurrent
volume groups. A concurrent resource group is one which may be active on more than one node at a
type. A concurrent volume group also shares the characteristic that it may be active on more than one
node at a time. This is also true for an enhanced concurrent VG; however, in a non-concurrent resource
group, the enhanced concurrent VG, while it may be active and not have a SCSI reserve residing on the
disk, it’s data is only normally accessed by one system at a time.
Pre-Reqs
In this document, it is assumed that the shared storage devices are already made available and
configured to AIX, and that the proper levels of RSCT and HACMP are already installed. Since utilizing
enhanced-concurrent volume groups, it is also necessary to make sure that bos.clvm.enh is installed.
This is not normally installed as part of a HACMP installation via the installp command.
Disk Heartbeat Details
This provides the ability to use existing shared disks, regardless of disk type, to provide a serial network
like heartbeat path. A benefit of this is that one need not dedicate the integrated serial ports for HACMP
heartbeats (if supported on the subject systems) or purchase an 8-port asynchronous adapter.
This feature utilizes a special area on the disk previously reserved for “Concurrent Capable” volume
groups (traditionally only for SSA disks). Since AIX 5.2 dropped support for the SSA concurrent volume
groups, this fit makes it available for use. This also means that the disk chosen for serial heartbeat can
be part of a data volume group. (Note Performance Concerns below)
The disk heart beating code went into the 2.2.1.30 version of RSCT. Some recommended APARs bring
that to 2.2.1.31. If you've got that level installed, and HACMP 5.1, you can use disk heart beating. The
relevant file to look for is /usr/sbin/rsct/bin/hats_diskhb_nim. Though it is supported mainly through
RSCT, we recommend AIX 5.2 when utilizing disk heartbeat.
To use disk heartbeats, no node can issue a SCSI reserve for the disk. This is because both nodes using it
for heart beating must be able to read and write to that disk. It is sufficient that the disk be in an
enhanced concurrent volume group to meet this requirement. (It should also be possible to use a disk
that is in no volume group for disk heart beating. RSCT certainly won't care; but HACMP SMIT panels
may not be particularly helpful in setting this up.)
Now, in HACMP 5.1 with AIX 5.1, enhanced concurrent mode volume groups can be used only in
concurrent (or "online on all available nodes") resource groups. This means that disk heart beating is
useful only to people running concurrent configurations, or who can allocate such a volume group/disk
(which is certainly possible, though perhaps an expensive approach). In other words, at HACMP 5.1 and
AIX 5.1, typical HACMP clusters (with a server and idle standby) will require an additional concurrent
resource group with a disk in an enhanced concurrent VG dedicated for heartbeat use. At AIX 5.2, disk
heartbeats can exist on an enhanced concurrent VG that resides in a non-concurrent resource group. At
AIX 5.2, one may also use the fast disk takeover feature in non-concurrent resource groups with
enhanced concurrent volume groups. With HACMP 5.1 and AIX 5.2, enhanced concurrent mode volume
groups can be used in serial access configurations for fast disk takeover, along with disk heart beating.
(AIX 5.2 requires RSCT 2.3.1.0 or later) That is, the facility becomes usable to the average customer,
without committment of additional resource, since disk heart beating can occur on a volume group used
for ordinary filesystem and logical volume activity.
Performance Concerns with Disk Heart Beating
Most modern disks take somewhere around 15 milliseconds to service an IO request, which means that
they can't do much more than 60 seeks per second. The sectors used for disk heart beating are part of
the VGDA, which is at the outer edge of the disk, and may not be near the application data. This means
that every time a disk heart beat is done, a seek will have to be done. Disk heart beating will typically
(with the default parameters) require four (4) seeks per second. That is each of two nodes will write to
the disk and read from the disk once/second, for a total of 4 IOPS. So, if possible, a disk should be
selected as a heart beat path that does not normally do more than about 50 seeks per second. The
filemon tool can be used to monitor the seek activity on a disk.
In cases where a disk must be used for heart beating that already has a high seek rate, it may be
necessary to change the heart beat timing parameters to prevent long write delays from being seen as a
failure.
The above cautions as stated apply to JBOD configurations, and should be modified based on the
technology of the disk subsystem:
• If the disk used for heart beating is in a controller that provides large amounts of cache - such as the
ESS - the number of seeks per second can be much larger
• If the disk used for heart beating is part of a RAID set without a caching front end controller, the disk
may be able to support fewer seeks, due to the extra activity required by RAID operations
Pros & Cons of using Disk Heart Beating
Pros:
1. No additional hardware needed.
2. Easier to span greater distances.
3. No loss in usable storage space and can use existing data volume groups.
4. Uses enhanced concurrent vgs which also allows for fast-disk takeover.
Cons:
1. Must be aware of the devices diskhb uses and administer devices properly*
2. Lose the forced down option of stopping cluster services because of enhanced concurrent vg usage.
*I have had a customer delete all their disk definitions and run cfgmgr again to clean up number holes in
their device definition list. When they did, obviously , the device names did not come back in the same
order as they were before. So the diskhb device assigned to HACMP, was no longer valid as a different
device was configured using the old device name and it was not part of an enhanced concurrent vg.
Hence diskhb no longer worked, and since the customer did not monitor their cluster either, they were
unaware that the diskhb no longer worked.
Configuring Disk Heartbeat
As mentioned previously, disk heartbeat utilizes enhanced-concurrent volume groups. If starting with a
new configuration of disks, you will want to create enhanced-concurrent volume groups, either
manually, or by utilizing C-SPOC. My example shows using C-SPOC which is the best practice to use here.
If you plan to use an existing volume group for disk heartbeats that is not enhanced concurrent, then
you will have to convert them to such using the chvg command. We recommend that the VG be active
on only one node, and that the application not be running when making this change run chvg –C vgname
to change the VG to enhanced concurrent mode. Vary it off, then run importvg –L vgname on the other
node to make it aware that the vg is now enhanced concurrent capable. If using this method, you can
skip to the “Creating Disk Heartbeat Devices and Network” section of this document.
Disk and VG Preparation
To be able to use C-SPOC successfully, it is required that some basic IP based topology already exists,
and that the storage devices have their PVIDs in both system’s ODMs. This can be verified by running
lspv on each system. If a PVID does not exist on each system, it is necessary to run chdev -l -a pv=yes on
each system. This will allow C-SPOC to match up the device(s) as known shared storage devices.
In this example, vpath0 on GT40 is the same virtual disk as vpath3 on SL55.
Use C-SPOC to create an Enhanced Concurrent volume group. In the following example, since vpath
devices are being used, the following smit screen paths were used.
Go to HACMP Concurrent Logical Volume smitty cl_admin Create a Concurrent Volume Group with
Data Concurrent Volume Groups Management Path Devices and press Enter
Choose the appropriate nodes, and then choose the appropriate shared storage devices based on pvids
(vpath0 and vpath3 in this example). Choose a name for the VG , desired PP size, make sure that
Enhanced Concurrent Mode is set to true and press Enter. (enhconcvg in this example). This will create
the shared enhanced-concurrent vg needed for our disk heartbeat. .
It’s a good idea to verify via lspv once this has completed to make sure the device and vg is show
appropriately as follows:
GT40#/ lspv
vpath0 000a7f5af78e0cf4 enhconcvg
SL55#/lspv
vpath3 000a7f5af78e0cf4 enhconcvg
Creating Disk Heartbeat Devices and Network
There are two different ways to do this. Since we have already created the enhanced concurrent vg, we
can use the discovery method (1) and let HA find it for us. Or we can do this manually via the Predefined
devices method (2). Following is an example of each.
1) Creating via Discover Method: (See Note)
Extended Enter smitty hacmp Press Discover HACMP-related Information from Configured
Nodes Configuration Enter
This will run automatically and create a clip_config file that contains the information it has discovered.
Once completed, go back to the Extended Configuration menu and chose:
Extended Topology Add Communication Configure HACMP Communication
Interfaces/Devices Configuration Add Discovered Communication Interface and Interfaces/Devices
Choose appropriate devices (ex. vpath0 and Communication Devices Devices vpath3)
Select Point-to-Point Pair of Discovered Communication Devices to Add
Move cursor to desired item and press F7. Use arrow keys to scroll.
ONE OR MORE items can be selected.
Press Enter AFTER making all selections.
# Node Device Device Path Pvid
> nodeGT40 vpath0 /dev/vpath0 000a7f5af78
> nodeSL55 vpath3 /dev/vpath3 000a7f5af78
Note: Base HA 5.1 appears to have a problem when using the Discovered Devices this method. If you get
this error: "ERROR: Invalid node name 000a7f5af78e0cf4".
Then you will need apar IY51594. Otherwise you will have to create via the Pre-Defined Devices method.
Once corrected, this section will be completed
2) Creating via Pre-Defined Devices Method
When using this method, it is necessary to create a diskhb network first, then assign the disk-node pair
devices to the network. Create the diskhb network as follows:
Extended Topology Extended Configuration smitty hacmp Add a Network to the HACMP cluster
Configure HACMP Networks Configuration Enter desired network name (ex. disknet1)—press choose
diskhb Enter
Extended Topology Extended Configuration smitty hacmp Add Configure HACMP Communication
Interfaces/Devices Configuration Add Pre-Defined Communication Interfaces and Communication
Interfaces/Devices Devices
Choose your diskhb Network Name Communication Devices
Add a Communication Device
Type or select values in entry fields.
Press Enter AFTER making all desired changes.
[Entry Fields]
* Device Name [GT40_hboverdisk]
* Network Type diskhb
* Network Name disknet1
* Device Path [/dev/vpath0]
* Node Name [GT40]
For Device Name, that is a unique name you can chose. It will show up in your topology under this
name, much like serial heartbeat and ttys have in the past.
For the Device Path, you want to put in /dev/. Then choose the corresponding node for this device and
device name (ex. GT40). Then press Enter.
You will repeat this process for the other node (ex. SL55) and the other device (vpath3). This will
complete both devices for the diskhb network.
Testing Disk Heartbeat Connectivity
Once the device and network definitions have been created, it is a good idea to test it and make sure
communications is working properly. If the volume group is varied on in normal mode on one of the
nodes, the test will probably not work.
/usr/sbin/rsct/bin/dhb_read is used to test the validity of a diskhb connection. The usage of dhb_read is
as follows:
dhb_read -p devicename //dump diskhb sector contents
dhb_read -p devicename -r //receive data over diskhb network
dhb_read -p devicename -t //transmit data over diskhb network
To test that disknet1, in the example configuration, can communicate from nodeB(ex. SL55) to nodeA
(ex. GT40), you would run the following commands:
On nodeA, enter:
dhb_read -p rvpath0 -r
On nodeB, enter:
dhb_read -p rvpath3 -t
Note: That the device name is raw device as designated with the “r” proceeding the device name.
If the link from nodeB to nodeA is operational, both nodes will display:
Link operating normally.
You can run this again and swap which node transmits and which one receives. To make the network
active, it is necessary to sync up the cluster. Since the volume group has not been added to the resource
group, we will sync up once instead of twice.
Add Shared Disk as a Shared Resource
In most cases you would have your diskhb device on a shared data vg. It is necessary to add that vg into
your resource group and synchronize the cluster.
Extended Extended Configuration smitty hacmp Resource Configuration >
Change/Show Extended Resource Group Configuration and press Enter. Resources and Attributes for a
Resource Group
Choose the appropriate resource group, enter the new vg (enhconcvg) into the volume group list and
press Enter.
Return to the top of the Extended Configuration menu and synchronize the cluster.
Monitor Disk Heartbeat
Once the cluster is up and running, you can monitor the activity of the disk (actually all) heartbeats via
lssrc -ls topsvcs. An example of the output follows:
Subsystem Group PID Status
topsvcs topsvcs 32108 active
Network Name Indx Defd Mbrs St Adapter ID Group ID
disknet1 [ 3] 2 2 S 255.255.10.0 255.255.10.1
disknet1 [ 3] rvpath3 0x86cd1b02 0x86cd1b4f
HB Interval = 2 secs. Sensitivity = 4 missed beats
Missed HBs: Total: 0 Current group: 0
Packets sent : 229 ICMP 0 Errors: 0 No mbuf: 0
Packets received: 217 ICMP 0 Dropped: 0
NIM's PID: 28724
Be aware that there is a grace period for heartbeats to start processing. This is normally around 60
seconds. So if you run this command quickly after starting the cluster, you may not see anything at all
until heartbeat processing is started after the grace period time has elapsed.
HACMP LOG FILES
HACMP LOG FILES
/usr/sbin/cluster/etc/rhosts --- to accept incoming communication from clcomdES (cluster
communucation enahanced security)
/usr/es/sbin/cluster/etc/rhosts
Note: If there is an unresolvable label in the /usr/es/sbin/cluster/etc/rhosts file,
then all clcomdES connections from remote nodes will be denied.
cluster manager clstrmgrES
cluster lock Daemon (clockdES)
cluster multi peer extension communication daemon (clsmuxpdES)
The clcomdES is used for cluster configuration operations such as cluster synchronisation
cluster management (C-SPoC) * Dynamic re-configuration DARE configuration. (DARE ) operation.
For clcomdES there should be atleast 20 MB free space in /var file system.
/var/hacmp/clcomd/clcomd.log --it requires 2 MB
/var/hacmp/clcomd/clcomdiag.log --it requires 18MB
Additional 1 MB required for
/var/hacmp/odmcache directory
clverfify.log also present in /var directory
/var/hacmp/clverify/current//* contains log for mcurrent execution of clverify
/var/hacmp/clverify/pass//* contains logs from the last passed verification
/var/hacmp/clverify/pass.prev//* contains log from the second last passed verification
/usr/sbin/cluster/etc/rhosts --- to accept incoming communication from clcomdES (cluster
communucation enahanced security)
/usr/es/sbin/cluster/etc/rhosts
Note: If there is an unresolvable label in the /usr/es/sbin/cluster/etc/rhosts file,
then all clcomdES connections from remote nodes will be denied.
cluster manager clstrmgrES
cluster lock Daemon (clockdES)
cluster multi peer extension communication daemon (clsmuxpdES)
The clcomdES is used for cluster configuration operations such as cluster synchronisation
cluster management (C-SPoC) * Dynamic re-configuration DARE configuration. (DARE ) operation.
For clcomdES there should be atleast 20 MB free space in /var file system.
/var/hacmp/clcomd/clcomd.log --it requires 2 MB
/var/hacmp/clcomd/clcomdiag.log --it requires 18MB
Additional 1 MB required for
/var/hacmp/odmcache directory
clverfify.log also present in /var directory
/var/hacmp/clverify/current//* contains log for mcurrent execution of clverify
/var/hacmp/clverify/pass//* contains logs from the last passed verification
/var/hacmp/clverify/pass.prev//* contains log from the second last passed verification
HACMP CAN BE CONFIGURED IN 3 WAYS.
HACMP CAN BE CONFIGURED IN 3 WAYS.
1. Rotating
2. Cascading
3. Mutual Failover
The cascading and rotating resource groups are the “classic”, pre-HA 5.1 types. The new “custom” type
of resource group has been introduced in HA 5.1 onwards.
Cascading resource group:
Upon node failure, a cascading resource group falls over to the available node with the next priority in
the node priority list.
Upon node reintegration into the cluster, a cascading resource group falls back to its home node by
default.
Cascading without fallback
Thisoption, this means whenever a primary node fails, the package will failover to the next available
node in the list and when the primary node comes online then the package will not fallback
automatically. We need to move package to its home node at a convenient time.
Rotating resource group:
This is almost similar to Cascading without fallback, whenever package failover to the standby nodes it
will never fallback to the primary node automatically, we need to move it manually at our convenience.
Mutual takeover:
Mutual takeover option, which means both the nodes in this type are active-active mode. Whenever fail
over happens the package on the failed node will move to the other active node and will run with
already existing package. Once the failed node comes online we can move the package manually to that
node.
1. Rotating
2. Cascading
3. Mutual Failover
The cascading and rotating resource groups are the “classic”, pre-HA 5.1 types. The new “custom” type
of resource group has been introduced in HA 5.1 onwards.
Cascading resource group:
Upon node failure, a cascading resource group falls over to the available node with the next priority in
the node priority list.
Upon node reintegration into the cluster, a cascading resource group falls back to its home node by
default.
Cascading without fallback
Thisoption, this means whenever a primary node fails, the package will failover to the next available
node in the list and when the primary node comes online then the package will not fallback
automatically. We need to move package to its home node at a convenient time.
Rotating resource group:
This is almost similar to Cascading without fallback, whenever package failover to the standby nodes it
will never fallback to the primary node automatically, we need to move it manually at our convenience.
Mutual takeover:
Mutual takeover option, which means both the nodes in this type are active-active mode. Whenever fail
over happens the package on the failed node will move to the other active node and will run with
already existing package. Once the failed node comes online we can move the package manually to that
node.
HACMP INFORMATION THROUGH COMMAND LINE
HACMP INFORMATION THROUGH COMMAND LINE
SET THE PATH FIRST TO RUN CLUSTER COMMANDS PEACEFULLY ( WITHOUT THINKING ABOUT THEIR PATHS)
# cd /usr/es/sbin/cluster
# export PATH=$PATH:$(pwd)
# cd utilities
# set -o vi
# export PATH=$PATH:$(pwd)
# cd ..
# cd sbin
# export PATH=$PATH:$(pwd)
# cd etc
# export PATH=$PATH:$(pwd)
#
INFO ABOUT VG
# cl_lsvg
cws: mksysvg
cws: sharevg
cws: shvg
pci: sharevg
pci: shvg
#
GETTING INFORMATION ABOUT RESOURCE GROUPS
SMALL INFO
# clRGinfo
-----------------------------------------------------------------------------
Group Name Type State Location
-----------------------------------------------------------------------------
ravirg non-concurrent OFFLINE pci
ONLINE cws
DETAILED INFO
# clshowres
Resource Group Name ravirg
Participating Node Name(s) pci cws
Startup Policy Online On Home Node Only
Fallover Policy Fallover To Next Priority Node In The List
Fallback Policy Fallback To Higher Priority Node In The List
Site Relationship ignore
Node Priority
Service IP Label pci_svc
Filesystems ALL
Filesystems Consistency Check fsck
Filesystems Recovery Method sequential
Filesystems/Directories to be exported
Filesystems to be NFS mounted
Network For NFS Mount
Volume Groups shvg sharevg
Concurrent Volume Groups
Use forced varyon for volume groups, if necessaryfalse
Disks
GMD Replicated Resources
PPRC Replicated Resources
ERCMF Replicated Resources
SVC PPRC Replicated Resources
AIX Connections Services
AIX Fast Connect Services
Shared Tape Resources
Application Servers
Highly Available Communication Links
Primary Workload Manager Class
Secondary Workload Manager Class
Delayed Fallback Timer
Miscellaneous Data
Automatically Import Volume Groups false
Inactive Takeover
SSA Disk Fencing false
Filesystems mounted before IP configured false
Run Time Parameters:
Node Name pci
Debug Level high
Format for hacmp.out Standard
Node Name cws
Debug Level high
Format for hacmp.out Standard
# clRGinfo
-----------------------------------------------------------------------------
Group Name Type State Location
-----------------------------------------------------------------------------
ravirg non-concurrent OFFLINE pci
ONLINE cws
GETTING INFORMATION ABOUT THE DISKS IN RESOURCE GROUP
# cllsdisk -g ravirg
000ac13302f48c19
000ac13311b97dc2
00fad1d4388d422c
#
GETTING INFORMATION ON THE FILE SYSTEMS IN RESOURCE GROUP
# cllsfs -g ravirg
/ravifs
/tstfs
#
GETTING INFORMATION ABOUT DISKS IN RESOURCE GROUP VG
# /usr/es/sbin/cluster/cspoc/cl_lsrgvgdisks
#Volume Group hdisk PVID Cluster Node
#---------------------------------------------------------------------
shvg hdisk3 000ac13302f48c19 cws ravirg
sharevg hdisk4 000ac13311b97dc2 cws ravirg
sharevg hdisk5 00fad1d4388d422c cws ravirg
#
COMPLETE CLUSTER INFORMATION
# /usr/es/sbin/cluster/utilities/cllscf
Cluster Name: ravicl
Cluster Connection Authentication Mode: Standard
Cluster Message Authentication Mode: None
Cluster Message Encryption: None
Use Persistent Labels for Communication: No
There were 1 networks defined: net_ether_01
There are 2 nodes in this cluster
NODE cws:
This node has 1 service IP label(s):
Service IP Label pci_svc:
IP address: 10.0.10.1
Hardware Address:
Network: net_ether_01
Attribute: public
Aliased Address?: Enable
Service IP Label pci_svc has 2 communication interfaces.
(Alternate Service) Communication Interface 1: cws_std
IP Address: 10.0.20.2
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
(Alternate Service) Communication Interface 2: cws
IP Address: 10.0.0.2
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
Service IP Label pci_svc has no communication interfaces for recovery.
NODE pci:
This node has 1 service IP label(s):
Service IP Label pci_svc:
IP address: 10.0.10.1
Hardware Address:
Network: net_ether_01
Attribute: public
Aliased Address?: Enable
Service IP Label pci_svc has 2 communication interfaces.
(Alternate Service) Communication Interface 1: pci_std
IP Address: 10.0.20.1
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
(Alternate Service) Communication Interface 2: pci_std1
IP Address: 193.9.200.224
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
Service IP Label pci_svc has no communication interfaces for recovery.
Breakdown of network connections:
Connections to network net_ether_01
Node cws is connected to network net_ether_01 by these interfaces:
cws_std
cws
pci_svc
Node pci is connected to network net_ether_01 by these interfaces:
pci_std
pci_std1
pci_svc
#
DETAIL INFORMATION ABOUT VG IN CLUSTER
# /usr/es/sbin/cluster/utilities/cllsvgdata
hdisk0:000ac133608d9e98:rootvg:10:0:active:0
hdisk1:000ac13382115287:rootvg:10:0:active:0
hdisk2:000ac13302f48c19:shvg:50:0:inactive:0
hdisk3:000ac13311b97dc2:sharevg:49:0:inactive:0
hdisk4:00fad1d4388d422c:sharevg:49:0:inactive:0
FREEMAJORS:45..48,51...
GETTING COMPLETE TOPOLOGY INFORMATION
# cltopinfo
Cluster Name: ravicl
Cluster Connection Authentication Mode: Standard
Cluster Message Authentication Mode: None
Cluster Message Encryption: None
Use Persistent Labels for Communication: No
There are 2 node(s) and 1 network(s) defined
NODE cws:
Network net_ether_01
pci_svc 10.0.10.1
cws_std 10.0.20.2
cws 10.0.0.2
NODE pci:
Network net_ether_01
pci_svc 10.0.10.1
pci_std 10.0.20.1
pci_std1 193.9.200.224
Resource Group ravirg
Startup Policy Online On Home Node Only
Fallover Policy Fallover To Next Priority Node In The List
Fallback Policy Fallback To Higher Priority Node In The List
Participating Nodes pci cws
Service IP Label pci_svc
#
SET THE PATH FIRST TO RUN CLUSTER COMMANDS PEACEFULLY ( WITHOUT THINKING ABOUT THEIR PATHS)
# cd /usr/es/sbin/cluster
# export PATH=$PATH:$(pwd)
# cd utilities
# set -o vi
# export PATH=$PATH:$(pwd)
# cd ..
# cd sbin
# export PATH=$PATH:$(pwd)
# cd etc
# export PATH=$PATH:$(pwd)
#
INFO ABOUT VG
# cl_lsvg
cws: mksysvg
cws: sharevg
cws: shvg
pci: sharevg
pci: shvg
#
GETTING INFORMATION ABOUT RESOURCE GROUPS
SMALL INFO
# clRGinfo
-----------------------------------------------------------------------------
Group Name Type State Location
-----------------------------------------------------------------------------
ravirg non-concurrent OFFLINE pci
ONLINE cws
DETAILED INFO
# clshowres
Resource Group Name ravirg
Participating Node Name(s) pci cws
Startup Policy Online On Home Node Only
Fallover Policy Fallover To Next Priority Node In The List
Fallback Policy Fallback To Higher Priority Node In The List
Site Relationship ignore
Node Priority
Service IP Label pci_svc
Filesystems ALL
Filesystems Consistency Check fsck
Filesystems Recovery Method sequential
Filesystems/Directories to be exported
Filesystems to be NFS mounted
Network For NFS Mount
Volume Groups shvg sharevg
Concurrent Volume Groups
Use forced varyon for volume groups, if necessaryfalse
Disks
GMD Replicated Resources
PPRC Replicated Resources
ERCMF Replicated Resources
SVC PPRC Replicated Resources
AIX Connections Services
AIX Fast Connect Services
Shared Tape Resources
Application Servers
Highly Available Communication Links
Primary Workload Manager Class
Secondary Workload Manager Class
Delayed Fallback Timer
Miscellaneous Data
Automatically Import Volume Groups false
Inactive Takeover
SSA Disk Fencing false
Filesystems mounted before IP configured false
Run Time Parameters:
Node Name pci
Debug Level high
Format for hacmp.out Standard
Node Name cws
Debug Level high
Format for hacmp.out Standard
# clRGinfo
-----------------------------------------------------------------------------
Group Name Type State Location
-----------------------------------------------------------------------------
ravirg non-concurrent OFFLINE pci
ONLINE cws
GETTING INFORMATION ABOUT THE DISKS IN RESOURCE GROUP
# cllsdisk -g ravirg
000ac13302f48c19
000ac13311b97dc2
00fad1d4388d422c
#
GETTING INFORMATION ON THE FILE SYSTEMS IN RESOURCE GROUP
# cllsfs -g ravirg
/ravifs
/tstfs
#
GETTING INFORMATION ABOUT DISKS IN RESOURCE GROUP VG
# /usr/es/sbin/cluster/cspoc/cl_lsrgvgdisks
#Volume Group hdisk PVID Cluster Node
#---------------------------------------------------------------------
shvg hdisk3 000ac13302f48c19 cws ravirg
sharevg hdisk4 000ac13311b97dc2 cws ravirg
sharevg hdisk5 00fad1d4388d422c cws ravirg
#
COMPLETE CLUSTER INFORMATION
# /usr/es/sbin/cluster/utilities/cllscf
Cluster Name: ravicl
Cluster Connection Authentication Mode: Standard
Cluster Message Authentication Mode: None
Cluster Message Encryption: None
Use Persistent Labels for Communication: No
There were 1 networks defined: net_ether_01
There are 2 nodes in this cluster
NODE cws:
This node has 1 service IP label(s):
Service IP Label pci_svc:
IP address: 10.0.10.1
Hardware Address:
Network: net_ether_01
Attribute: public
Aliased Address?: Enable
Service IP Label pci_svc has 2 communication interfaces.
(Alternate Service) Communication Interface 1: cws_std
IP Address: 10.0.20.2
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
(Alternate Service) Communication Interface 2: cws
IP Address: 10.0.0.2
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
Service IP Label pci_svc has no communication interfaces for recovery.
NODE pci:
This node has 1 service IP label(s):
Service IP Label pci_svc:
IP address: 10.0.10.1
Hardware Address:
Network: net_ether_01
Attribute: public
Aliased Address?: Enable
Service IP Label pci_svc has 2 communication interfaces.
(Alternate Service) Communication Interface 1: pci_std
IP Address: 10.0.20.1
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
(Alternate Service) Communication Interface 2: pci_std1
IP Address: 193.9.200.224
Network: net_ether_01
Attribute: public
Alias address for heartbeat:
Service IP Label pci_svc has no communication interfaces for recovery.
Breakdown of network connections:
Connections to network net_ether_01
Node cws is connected to network net_ether_01 by these interfaces:
cws_std
cws
pci_svc
Node pci is connected to network net_ether_01 by these interfaces:
pci_std
pci_std1
pci_svc
#
DETAIL INFORMATION ABOUT VG IN CLUSTER
# /usr/es/sbin/cluster/utilities/cllsvgdata
hdisk0:000ac133608d9e98:rootvg:10:0:active:0
hdisk1:000ac13382115287:rootvg:10:0:active:0
hdisk2:000ac13302f48c19:shvg:50:0:inactive:0
hdisk3:000ac13311b97dc2:sharevg:49:0:inactive:0
hdisk4:00fad1d4388d422c:sharevg:49:0:inactive:0
FREEMAJORS:45..48,51...
GETTING COMPLETE TOPOLOGY INFORMATION
# cltopinfo
Cluster Name: ravicl
Cluster Connection Authentication Mode: Standard
Cluster Message Authentication Mode: None
Cluster Message Encryption: None
Use Persistent Labels for Communication: No
There are 2 node(s) and 1 network(s) defined
NODE cws:
Network net_ether_01
pci_svc 10.0.10.1
cws_std 10.0.20.2
cws 10.0.0.2
NODE pci:
Network net_ether_01
pci_svc 10.0.10.1
pci_std 10.0.20.1
pci_std1 193.9.200.224
Resource Group ravirg
Startup Policy Online On Home Node Only
Fallover Policy Fallover To Next Priority Node In The List
Fallback Policy Fallback To Higher Priority Node In The List
Participating Nodes pci cws
Service IP Label pci_svc
#
HACMP QUICK REFERENCE AND INTERVIEW PREPERATION
HACMP QUICK REFERENCE AND INTERVIEW PREPERATION
DOCUMENT CREATED BY SANDEEP TANTI
TABLE OF CONTENTS
TABLE OF CONTENTS .................................................................................................................................... 1
HACMP BASICS ............................................................................................................................................. 2
USEFUL HACMP COMMANDS ....................................................................................................................... 3
STEPS TO CONFIGURE HACMP: ..................................................................................................................... 4
TESTING HACMP: HA FAILOVER SCENARIOS ............................................................................................... 11
HACMP V5.X DISK HEARTBEAT DEVICE CONFIGURATION .......................................................................... 13
Monitor Disk Heartbeat .............................................................................................................................. 22
HACMP LOG FILES ...................................................................................................................................... 23
DOCUMENT CREATED BY SANDEEP TANTI
TABLE OF CONTENTS
TABLE OF CONTENTS .................................................................................................................................... 1
HACMP BASICS ............................................................................................................................................. 2
USEFUL HACMP COMMANDS ....................................................................................................................... 3
STEPS TO CONFIGURE HACMP: ..................................................................................................................... 4
TESTING HACMP: HA FAILOVER SCENARIOS ............................................................................................... 11
HACMP V5.X DISK HEARTBEAT DEVICE CONFIGURATION .......................................................................... 13
Monitor Disk Heartbeat .............................................................................................................................. 22
HACMP LOG FILES ...................................................................................................................................... 23
C program-6
1. /* Write a C program to read a string and check whether it is *
* a palindrome or not (without using library functions). Output *
* the given string along with suitable message */
#include
#include
main()
{
char string[25], revString[25]={'\0'};
int i,length = 0, flag = 0;
clrscr();
fflush(stdin);
printf("Enter a string\n");
gets(string);
for (i=0; string[i] != '\0'; i++) /*keep going through each */
{ /*character of the string */
length++; /*till its end */
}
for (i=length-1; i >= 0 ; i--)
{
revString[length-i-1] = string[i];
}
/*Compare the input string and its reverse. If both are equal
then the input string is palindrome. Otherwise it is
not a palindrome */
for (i=0; i < length ; i++) { if (revString[i] == string[i]) flag = 1; else flag = 0; } if (flag == 1) printf ("%s is a palindrome\n", string); else printf("%s is not a palindrome\n", string); } /*End of main()*/ /*---------------------------------------------------- Output RUN 1 Enter a string madam madam is a palindrome RUN 2 Enter a string Madam Madam is not a palindrome RUN 3 Enter a string good good is not a palindrome ----------------------------------------------------------*/ ********************************************************************************* 2. /* Write a C program to read two strings and concatenate them * * (without using library functions). Output the concatenated * * string along with the given string */ #include
#include
main()
{
char string1[20], string2[20];
int i,j,pos;
strset(string1, '\0'); /*set all occurrences in two strings to NULL*/
strset(string2,'\0');
printf("Enter the first string :");
gets(string1);
fflush(stdin);
printf("Enter the second string:");
gets(string2);
printf("First string = %s\n", string1);
printf("Second string = %s\n", string2);
/*To concate the second stribg to the end of the string
travserse the first to its end and attach the second string*/
for (i=0; string1[i] != '\0'; i++)
{
; /*null statement: simply trvsering the string1*/
}
pos = i;
for (i=pos,j=0; string2[j]!='\0'; i++)
{
string1[i] = string2[j++];
}
string1[i]='\0'; /*set the last character of string1 to NULL*/
printf("Concatenated string = %s\n", string1);
}
/*---------------------------------------
Output
Enter the first string :CD-
Enter the second string:ROM
First string = CD-
Second string = ROM
Concatenated string = CD-ROM
----------------------------------------*/
*********************************************************************
3. /* Write a C program to read an English sentence and replace*
* lowercase characters by uppercase and vice-versa. Output *
* the given sentence as well as the case covrted sentence on*
* two different lines. */
#include
#include
#include
main()
{
char sentence[100];
int count, ch, i;
clrscr();
printf("Enter a sentence\n");
for(i=0; (sentence[i] = getchar())!='\n'; i++)
{
;
}
sentence[i]='\0';
count = i; /*shows the number of chars accepted in a sentence*/
printf("The given sentence is : %s",sentence);
printf("\nCase changed sentence is: ");
for(i=0; i < count; i++) { ch = islower(sentence[i]) ? toupper(sentence[i]) : tolower(sentence[i]); putchar(ch); } } /*End of main()*/ /*------------------------------ Output Enter a sentence Mera Bharat Mahan The given sentence is : Mera Bhaaat Mahan Case changed sentence is: mERA bHARAT mAHAN ------------------------------------------------*/ ****************************************************************** 4. /* Write a C program read a sentence and count the number of * * number of vowels and consonants in the given sentence. * * Output the results on two lines with suitable headings */ #include
main()
{
char sentence[80];
int i, vowels=0, consonants=0, special = 0;
clrscr();
printf("Enter a sentence\n");
gets(sentence);
for(i=0; sentence[i] != '\0'; i++)
{
if((sentence[i] == 'a'||sentence[i] == 'e'||sentence[i] == 'i'||
sentence[i] == 'o'||sentence[i] == 'u') ||(sentence[i] == 'A'||
sentence[i] == 'E'||sentence[i] == 'I'|| sentence[i] == 'O'||
sentence[i] == 'U'))
{
vowels = vowels + 1;
}
else
{
consonants = consonants + 1;
}
if (sentence[i] =='\t' ||sentence[i] =='\0' || sentence[i] ==' ')
{
special = special + 1;
}
}
consonants = consonants - special;
printf("No. of vowels in %s = %d\n", sentence, vowels);
printf("No. of consonants in %s = %d\n", sentence, consonants);
}
/*------------------------
Output
Enter a sentence
Good Morning
No. of vowels in Good Morning = 4
No. of consonants in Good Morning = 7
-----------------------------------------*/
***************************************************************************
5. /* Write a C program to read N names, store them in the form *
* of an array and sort them in alphabetical order. Output the*
* give names and the sorted names in two columns side by side*
* wih suitable heading */
#include
#include
main()
{
char name[10][8], Tname[10][8], temp[8];
int i, j, N;
clrscr();
printf("Enter the value of N\n");
scanf("%d", &N);
printf("Enter %d names\n", N);
for(i=0; i< N ; i++) { scanf("%s",name[i]); strcpy (Tname[i], name[i]); } for(i=0; i < N-1 ; i++) { for(j=i+1; j< N; j++) { if(strcmpi(name[i],name[j]) > 0)
{
strcpy(temp,name[i]);
strcpy(name[i],name[j]);
strcpy(name[j],temp);
}
}
}
printf("\n----------------------------------------\n");
printf("Input Names\tSorted names\n");
printf("----------------------------------------\n");
for(i=0; i< N ; i++)
{
printf("%s\t\t%s\n",Tname[i], name[i]);
}
printf("----------------------------------------\n");
} /* End of main() */
/*--------------------------------
Output
Enter the value of N
3
Enter 3 names
Monica
Laxmi
Anand
----------------------------------------
Input Names Sorted names
----------------------------------------
Monica Anand
Laxmi Laxmi
Anand Monica
----------------------------------------
---------------------------------------- */
* a palindrome or not (without using library functions). Output *
* the given string along with suitable message */
#include
#include
main()
{
char string[25], revString[25]={'\0'};
int i,length = 0, flag = 0;
clrscr();
fflush(stdin);
printf("Enter a string\n");
gets(string);
for (i=0; string[i] != '\0'; i++) /*keep going through each */
{ /*character of the string */
length++; /*till its end */
}
for (i=length-1; i >= 0 ; i--)
{
revString[length-i-1] = string[i];
}
/*Compare the input string and its reverse. If both are equal
then the input string is palindrome. Otherwise it is
not a palindrome */
for (i=0; i < length ; i++) { if (revString[i] == string[i]) flag = 1; else flag = 0; } if (flag == 1) printf ("%s is a palindrome\n", string); else printf("%s is not a palindrome\n", string); } /*End of main()*/ /*---------------------------------------------------- Output RUN 1 Enter a string madam madam is a palindrome RUN 2 Enter a string Madam Madam is not a palindrome RUN 3 Enter a string good good is not a palindrome ----------------------------------------------------------*/ ********************************************************************************* 2. /* Write a C program to read two strings and concatenate them * * (without using library functions). Output the concatenated * * string along with the given string */ #include
#include
main()
{
char string1[20], string2[20];
int i,j,pos;
strset(string1, '\0'); /*set all occurrences in two strings to NULL*/
strset(string2,'\0');
printf("Enter the first string :");
gets(string1);
fflush(stdin);
printf("Enter the second string:");
gets(string2);
printf("First string = %s\n", string1);
printf("Second string = %s\n", string2);
/*To concate the second stribg to the end of the string
travserse the first to its end and attach the second string*/
for (i=0; string1[i] != '\0'; i++)
{
; /*null statement: simply trvsering the string1*/
}
pos = i;
for (i=pos,j=0; string2[j]!='\0'; i++)
{
string1[i] = string2[j++];
}
string1[i]='\0'; /*set the last character of string1 to NULL*/
printf("Concatenated string = %s\n", string1);
}
/*---------------------------------------
Output
Enter the first string :CD-
Enter the second string:ROM
First string = CD-
Second string = ROM
Concatenated string = CD-ROM
----------------------------------------*/
*********************************************************************
3. /* Write a C program to read an English sentence and replace*
* lowercase characters by uppercase and vice-versa. Output *
* the given sentence as well as the case covrted sentence on*
* two different lines. */
#include
#include
#include
main()
{
char sentence[100];
int count, ch, i;
clrscr();
printf("Enter a sentence\n");
for(i=0; (sentence[i] = getchar())!='\n'; i++)
{
;
}
sentence[i]='\0';
count = i; /*shows the number of chars accepted in a sentence*/
printf("The given sentence is : %s",sentence);
printf("\nCase changed sentence is: ");
for(i=0; i < count; i++) { ch = islower(sentence[i]) ? toupper(sentence[i]) : tolower(sentence[i]); putchar(ch); } } /*End of main()*/ /*------------------------------ Output Enter a sentence Mera Bharat Mahan The given sentence is : Mera Bhaaat Mahan Case changed sentence is: mERA bHARAT mAHAN ------------------------------------------------*/ ****************************************************************** 4. /* Write a C program read a sentence and count the number of * * number of vowels and consonants in the given sentence. * * Output the results on two lines with suitable headings */ #include
main()
{
char sentence[80];
int i, vowels=0, consonants=0, special = 0;
clrscr();
printf("Enter a sentence\n");
gets(sentence);
for(i=0; sentence[i] != '\0'; i++)
{
if((sentence[i] == 'a'||sentence[i] == 'e'||sentence[i] == 'i'||
sentence[i] == 'o'||sentence[i] == 'u') ||(sentence[i] == 'A'||
sentence[i] == 'E'||sentence[i] == 'I'|| sentence[i] == 'O'||
sentence[i] == 'U'))
{
vowels = vowels + 1;
}
else
{
consonants = consonants + 1;
}
if (sentence[i] =='\t' ||sentence[i] =='\0' || sentence[i] ==' ')
{
special = special + 1;
}
}
consonants = consonants - special;
printf("No. of vowels in %s = %d\n", sentence, vowels);
printf("No. of consonants in %s = %d\n", sentence, consonants);
}
/*------------------------
Output
Enter a sentence
Good Morning
No. of vowels in Good Morning = 4
No. of consonants in Good Morning = 7
-----------------------------------------*/
***************************************************************************
5. /* Write a C program to read N names, store them in the form *
* of an array and sort them in alphabetical order. Output the*
* give names and the sorted names in two columns side by side*
* wih suitable heading */
#include
#include
main()
{
char name[10][8], Tname[10][8], temp[8];
int i, j, N;
clrscr();
printf("Enter the value of N\n");
scanf("%d", &N);
printf("Enter %d names\n", N);
for(i=0; i< N ; i++) { scanf("%s",name[i]); strcpy (Tname[i], name[i]); } for(i=0; i < N-1 ; i++) { for(j=i+1; j< N; j++) { if(strcmpi(name[i],name[j]) > 0)
{
strcpy(temp,name[i]);
strcpy(name[i],name[j]);
strcpy(name[j],temp);
}
}
}
printf("\n----------------------------------------\n");
printf("Input Names\tSorted names\n");
printf("----------------------------------------\n");
for(i=0; i< N ; i++)
{
printf("%s\t\t%s\n",Tname[i], name[i]);
}
printf("----------------------------------------\n");
} /* End of main() */
/*--------------------------------
Output
Enter the value of N
3
Enter 3 names
Monica
Laxmi
Anand
----------------------------------------
Input Names Sorted names
----------------------------------------
Monica Anand
Laxmi Laxmi
Anand Monica
----------------------------------------
---------------------------------------- */
C program-5
1. /* Write a C program to input real numbers and find the *
* mean, variance and standard deviation */
#include
#include
#define MAXSIZE 10
main()
{
float x[MAXSIZE];
int i, n;
float avrg, var, SD, sum=0, sum1=0;
clrscr();
printf("Enter the value of N\n");
scanf("%d", &n);
printf("Enter %d real numbers\n",n);
for(i=0; i
#define MAX 4
main()
{
int a[MAX], i, l1,l2, s, temp;
clrscr();
printf("Enter %d integer numbers\n", MAX);
for (i=0; i < MAX; i++) { scanf("%d", &a[i]); } printf("Input interger are\n"); for (i=0; i < MAX; i++) { printf("%5d", a[i]); } printf("\n"); l1 = a[0]; /*assume first element of array is the first largest*/ l2 = a[1]; /*assume first element of array is the second largest*/ if (l1 < l2) { temp = l1; l1 = l2; l2 = temp; } for (i=2;i<4;i++) { if (a[i] >= l1)
{
l2 = l1;
l1 = a[i];
}
else if(a[i] > l2)
{
l2= a[i];
}
}
printf("\n%d is the first largest\n", l1);
printf("%d is the second largest\n", l2);
printf("\nAverage of %d and %d = %d\n", l1,l2, (l1+l2)/2);
}
/*-----------------------------------
Output
RUN 1
Enter 4 integer numbers
45
33
21
10
Input interger are
45 33 21 10
45 is the first largest
33 is the second largest
Average of 45 and 33 = 39
RUN 2
Enter 4 integer numbers
12
90
54
67
Input interger are
12 90 54 67
90 is the first largest
67 is the second largest
Average of 90 and 67 = 78
RUN 3
Enter 4 integer numbers
100
200
300
400
Input interger are
100 200 300 400
400 is the first largest
300 is the second largest
Average of 400 and 300 = 350
------------------------------------*/
**************************************************************************
3. /* Write a C program to evaluate the given polynomial *
* P(x)=AnXn + An-1Xn-1 + An-2Xn-2+... +A1X + A0, by *
* reading its coefficents into an array. [Hint:Rewrite *
* the polynomial as *
* P(x) = a0 + x(a1+x(a2+x(a3+x(a4+x(...x(an-1+xan)))) *
* and evalate the function starting from the inner loop]*/
#include
#define MAXSIZE 10
main()
{
int a[MAXSIZE];
int i, N,power;
float x, polySum;
clrscr();
printf("Enter the order of the polynomial\n");
scanf("%d", &N);
printf("Enter the value of x\n");
scanf("%f", &x);
/*Read the coefficients into an array*/
printf("Enter %d coefficients\n",N+1);
for (i=0;i <= N;i++) { scanf("%d",&a[i]); } polySum = a[0]; for (i=1;i<= N;i++) { polySum = polySum * x + a[i]; } power = N; /*power--;*/ printf("Given polynomial is:\n"); for (i=0;i<= N;i++) { if (power < 0) { break; } /* printing proper polynomial function*/ if (a[i] > 0)
printf(" + ");
else if (a[i] < 0) printf(" - "); else printf (" "); printf("%dx^%d ",abs(a[i]),power--); } printf("\nSum of the polynomial = %6.2f\n",polySum); } /*------------------ Output RUN 1 Enter the order of the polynomial 2 Enter the value of x 2 Enter 3 coefficients 3 2 6 Given polynomial is: + 3x^2 + 2x^1 + 6x^0 Sum of the polynomial = 22.00 RUN 2 Enter the order of the polynomial 4 Enter the value of x 1 Enter 5 coefficients 3 -5 6 8 -9 Given polynomial is: + 3x^4 - 5x^3 + 6x^2 + 8x^1 - 9x^0 Sum of the polynomial = 3.00 --------------------*/ ********************************************************************* 4. /* Write a C program to read two matrices A (MxN) and B(MxN)* * and perform addition OR subtraction of A and B. Find the * * trace of the resultant matrix. Output the given matrix, * * their sum or Differences and the trace. */ #include
main()
{
int A[10][10], B[10][10], sumat[10][10], diffmat[10][10];
int i, j, M,N, option;
void trace (int arr[][10], int M, int N);
clrscr();
printf("Enter the order of the matrice A and B\n");
scanf("%d %d", &M, &N);
printf("Enter the elements of matrix A\n");
for(i=0; i
main()
{
int i,j,M,N;
int A[10][10], B[10][10];
int transpose(int A[][10], int r, int c); /*Function prototype*/
clrscr();
printf("Enter the order of matrix A\n");
scanf("%d %d", &M, &N);
printf("Enter the elements of matrix\n");
for(i=0;i
{
for(j=0;j
{
scanf("%d",&A[i][j]);
}
}
printf("Matrix A is\n");
for(i=0;i
{
for(j=0;j
{
printf("%3d",A[i][j]);
}
printf("\n");
}
/* Finding Transpose of matrix*/
for(i=0;i
{
for(j=0;j
{
B[i][j] = A[j][i];
}
}
printf("Its Transpose is\n");
for(i=0;i
{
for(j=0;j
{
printf("%3d",B[i][j]);
}
printf("\n");
}
} /*End of main()*/
/*---------------------------------------
Output
Enter the order of matrix A
3 3
Enter the elements of matrix
1
2
3
4
5
6
7
8
9
MatrixxA is
1 2 3
4 5 6
7 8 9
Its Transpose is
1 4 7
2 5 8
3 6 9
-----------------------------*/
* mean, variance and standard deviation */
#include
#include
#define MAXSIZE 10
main()
{
float x[MAXSIZE];
int i, n;
float avrg, var, SD, sum=0, sum1=0;
clrscr();
printf("Enter the value of N\n");
scanf("%d", &n);
printf("Enter %d real numbers\n",n);
for(i=0; i
#define MAX 4
main()
{
int a[MAX], i, l1,l2, s, temp;
clrscr();
printf("Enter %d integer numbers\n", MAX);
for (i=0; i < MAX; i++) { scanf("%d", &a[i]); } printf("Input interger are\n"); for (i=0; i < MAX; i++) { printf("%5d", a[i]); } printf("\n"); l1 = a[0]; /*assume first element of array is the first largest*/ l2 = a[1]; /*assume first element of array is the second largest*/ if (l1 < l2) { temp = l1; l1 = l2; l2 = temp; } for (i=2;i<4;i++) { if (a[i] >= l1)
{
l2 = l1;
l1 = a[i];
}
else if(a[i] > l2)
{
l2= a[i];
}
}
printf("\n%d is the first largest\n", l1);
printf("%d is the second largest\n", l2);
printf("\nAverage of %d and %d = %d\n", l1,l2, (l1+l2)/2);
}
/*-----------------------------------
Output
RUN 1
Enter 4 integer numbers
45
33
21
10
Input interger are
45 33 21 10
45 is the first largest
33 is the second largest
Average of 45 and 33 = 39
RUN 2
Enter 4 integer numbers
12
90
54
67
Input interger are
12 90 54 67
90 is the first largest
67 is the second largest
Average of 90 and 67 = 78
RUN 3
Enter 4 integer numbers
100
200
300
400
Input interger are
100 200 300 400
400 is the first largest
300 is the second largest
Average of 400 and 300 = 350
------------------------------------*/
**************************************************************************
3. /* Write a C program to evaluate the given polynomial *
* P(x)=AnXn + An-1Xn-1 + An-2Xn-2+... +A1X + A0, by *
* reading its coefficents into an array. [Hint:Rewrite *
* the polynomial as *
* P(x) = a0 + x(a1+x(a2+x(a3+x(a4+x(...x(an-1+xan)))) *
* and evalate the function starting from the inner loop]*/
#include
#define MAXSIZE 10
main()
{
int a[MAXSIZE];
int i, N,power;
float x, polySum;
clrscr();
printf("Enter the order of the polynomial\n");
scanf("%d", &N);
printf("Enter the value of x\n");
scanf("%f", &x);
/*Read the coefficients into an array*/
printf("Enter %d coefficients\n",N+1);
for (i=0;i <= N;i++) { scanf("%d",&a[i]); } polySum = a[0]; for (i=1;i<= N;i++) { polySum = polySum * x + a[i]; } power = N; /*power--;*/ printf("Given polynomial is:\n"); for (i=0;i<= N;i++) { if (power < 0) { break; } /* printing proper polynomial function*/ if (a[i] > 0)
printf(" + ");
else if (a[i] < 0) printf(" - "); else printf (" "); printf("%dx^%d ",abs(a[i]),power--); } printf("\nSum of the polynomial = %6.2f\n",polySum); } /*------------------ Output RUN 1 Enter the order of the polynomial 2 Enter the value of x 2 Enter 3 coefficients 3 2 6 Given polynomial is: + 3x^2 + 2x^1 + 6x^0 Sum of the polynomial = 22.00 RUN 2 Enter the order of the polynomial 4 Enter the value of x 1 Enter 5 coefficients 3 -5 6 8 -9 Given polynomial is: + 3x^4 - 5x^3 + 6x^2 + 8x^1 - 9x^0 Sum of the polynomial = 3.00 --------------------*/ ********************************************************************* 4. /* Write a C program to read two matrices A (MxN) and B(MxN)* * and perform addition OR subtraction of A and B. Find the * * trace of the resultant matrix. Output the given matrix, * * their sum or Differences and the trace. */ #include
main()
{
int A[10][10], B[10][10], sumat[10][10], diffmat[10][10];
int i, j, M,N, option;
void trace (int arr[][10], int M, int N);
clrscr();
printf("Enter the order of the matrice A and B\n");
scanf("%d %d", &M, &N);
printf("Enter the elements of matrix A\n");
for(i=0; i
main()
{
int i,j,M,N;
int A[10][10], B[10][10];
int transpose(int A[][10], int r, int c); /*Function prototype*/
clrscr();
printf("Enter the order of matrix A\n");
scanf("%d %d", &M, &N);
printf("Enter the elements of matrix\n");
for(i=0;i
for(j=0;j
scanf("%d",&A[i][j]);
}
}
printf("Matrix A is\n");
for(i=0;i
for(j=0;j
printf("%3d",A[i][j]);
}
printf("\n");
}
/* Finding Transpose of matrix*/
for(i=0;i
for(j=0;j
B[i][j] = A[j][i];
}
}
printf("Its Transpose is\n");
for(i=0;i
for(j=0;j
printf("%3d",B[i][j]);
}
printf("\n");
}
} /*End of main()*/
/*---------------------------------------
Output
Enter the order of matrix A
3 3
Enter the elements of matrix
1
2
3
4
5
6
7
8
9
MatrixxA is
1 2 3
4 5 6
7 8 9
Its Transpose is
1 4 7
2 5 8
3 6 9
-----------------------------*/
C Program-4
1. /* Write a C program to find the sum of odd numbers and *
* sum of even numbers from 1 to N. Output the computed *
* sums on two different lines with suitable headings */
#include
main()
{
int i, N, oddSum = 0, evenSum = 0;
clrscr();
printf("Enter the value of N\n");
scanf ("%d", &N);
for (i=1; i <=N; i++) { if (i % 2 == 0) evenSum = evenSum + i; else oddSum = oddSum + i; } printf ("Sum of all odd numbers = %d\n", oddSum); printf ("Sum of all even numbers = %d\n", evenSum); } /*----------------------------- Output RUN1 Enter the value of N 10 Sum of all odd numbers = 25 Sum of all even numbers = 30 RUN2 Enter the value of N 50 Sum of all odd numbers = 625 Sum of all even numbers = 650 ------------------------------*/ ***************************************************************** 2. /* Write a C program to reverse a given integer number and check * * whether it is a palindrome. Output the given numbers with suitable* * message */ #include
main()
{
int num, rev = 0, found = 0, temp, digit;
clrscr();
printf("Enter an integer\n");
scanf("%d", &num);
temp = num;
while(num > 0)
{
digit = num % 10;
rev = rev * 10 + digit;
num /= 10;
}
printf("Given number is = %d\n", temp);
printf("Its reverse is = %d\n", rev);
if(temp == rev )
printf("Number is a palindrome\n");
else
printf("Number is not a palindrome\n");
}
/*------------------------
Output
RUN 1
Enter an integer
12321
Given number is = 12321
Its reverse is = 12321
Number is a palindrome
RUN 2
Enter an integer
3456
Given number is = 3456
Its reverse is = 6543
Number is not a palindrome
-----------------------------------*/
****************************************************************
3. /* Write a C program to find the value of sin(x) using the series *
* up to the given accuracy (without using user defined function) *
* Also print sin(x) using library function. */
#include
#include
#include
main()
{
float acc, term, den, x, sinx=0, sinval;
int i, n, x1;
clrscr();
printf("Enter the value of x (in degrees)\n");
scanf("%f",&x);
x1 = x;
/* Degrees to radians*/
x = x*(3.142/180.0);
sinval = sin(x);
printf("Enter the accuary for the result\n");
scanf("%f", &acc);
term = x;
sinx = term;
n = 1;
do
{
den = 2*n*(2*n+1);
term = -term * x * x / den;
sinx = sinx + term;
n = n + 1;
} while(acc <= fabs(sinval - sinx)); printf("Sum of the sine series = %f\n", sinx); printf("Using Library function sin(%d) = %f\n", x1,sin(x)); } /*End of main() */ /*------------------------------ Output Enter the value of x (in degrees) 30 Enter the accuary for the result 0.000001 Sum of the sine series = 0.500059 Using Library function sin(30) = 0.500059 RUN 2 Enter the value of x (in degrees) 45 Enter the accuary for the result 0.0001 Sum of the sine series = 0.707215 Using Library function sin(45) = 0.707179 ---------------------------------------------*/ ******************************************************************************** 4. /* Write a C program to find the value of cos(x) using the series * * up to the given accuracy (without using user defined function) * * Also print cos(x) using library function. */ #include
#include
#include
main()
{
float acc, term, den, x, cosx=0, cosval;
int i, n, x1;
clrscr();
printf("Enter the value of x (in degrees)\n");
scanf("%f",&x);
x1 = x;
/* Degrees to radians*/
x = x*(3.142/180.0);
cosval = cos(x);
printf("Enter the accuary for the result\n");
scanf("%f", &acc);
term = 1;
cosx = term;
n = 1;
do
{
den = 2*n*(2*n-1);
term = -term * x * x / den;
cosx = cosx + term;
n = n + 1;
} while(acc <= fabs(cosval - cosx)); printf("Sum of the cosine series = %f\n", cosx); printf("Using Library function cos(%d) = %f\n", x1,cos(x)); } /*End of main() */ /*------------------------------ Output Enter the value of x (in degrees) 30 Enter the accuary for the result 0.000001 Sum of the cosine series = 0.865991 Using Library function cos(30) = 0.865991 RUN 2 Enter the value of x (in degrees) 45 Enter the accuary for the result 0.0001 Sum of the cosine series = 0.707031 Using Library function cos(45) = 0.707035 ---------------------------------------------*/ **************************************************************************** 5. /* Write a C program to check whether a given number is prime or not * * and output the given number with suitable message */ #include
#include
main()
{
int num, j, flag;
clrscr();
printf("Enter a number\n");
scanf("%d", &num);
if ( num <= 1)
{
printf("%d is not a prime numbers\n", num);
exit(1);
}
flag = 0;
for ( j=2; j<= num/2; j++)
{
if( ( num % j ) == 0)
{
flag = 1;
break;
}
}
if(flag == 0)
printf("%d is a prime number\n",num);
else
printf("%d is not a prime number\n", num);
}
/*------------------------
Output
RUN 1
Enter a number
34
34 is not a prime number
RUN 2
Enter a number
29
29 is a prime number
-----------------------------*/
* sum of even numbers from 1 to N. Output the computed *
* sums on two different lines with suitable headings */
#include
main()
{
int i, N, oddSum = 0, evenSum = 0;
clrscr();
printf("Enter the value of N\n");
scanf ("%d", &N);
for (i=1; i <=N; i++) { if (i % 2 == 0) evenSum = evenSum + i; else oddSum = oddSum + i; } printf ("Sum of all odd numbers = %d\n", oddSum); printf ("Sum of all even numbers = %d\n", evenSum); } /*----------------------------- Output RUN1 Enter the value of N 10 Sum of all odd numbers = 25 Sum of all even numbers = 30 RUN2 Enter the value of N 50 Sum of all odd numbers = 625 Sum of all even numbers = 650 ------------------------------*/ ***************************************************************** 2. /* Write a C program to reverse a given integer number and check * * whether it is a palindrome. Output the given numbers with suitable* * message */ #include
main()
{
int num, rev = 0, found = 0, temp, digit;
clrscr();
printf("Enter an integer\n");
scanf("%d", &num);
temp = num;
while(num > 0)
{
digit = num % 10;
rev = rev * 10 + digit;
num /= 10;
}
printf("Given number is = %d\n", temp);
printf("Its reverse is = %d\n", rev);
if(temp == rev )
printf("Number is a palindrome\n");
else
printf("Number is not a palindrome\n");
}
/*------------------------
Output
RUN 1
Enter an integer
12321
Given number is = 12321
Its reverse is = 12321
Number is a palindrome
RUN 2
Enter an integer
3456
Given number is = 3456
Its reverse is = 6543
Number is not a palindrome
-----------------------------------*/
****************************************************************
3. /* Write a C program to find the value of sin(x) using the series *
* up to the given accuracy (without using user defined function) *
* Also print sin(x) using library function. */
#include
#include
#include
main()
{
float acc, term, den, x, sinx=0, sinval;
int i, n, x1;
clrscr();
printf("Enter the value of x (in degrees)\n");
scanf("%f",&x);
x1 = x;
/* Degrees to radians*/
x = x*(3.142/180.0);
sinval = sin(x);
printf("Enter the accuary for the result\n");
scanf("%f", &acc);
term = x;
sinx = term;
n = 1;
do
{
den = 2*n*(2*n+1);
term = -term * x * x / den;
sinx = sinx + term;
n = n + 1;
} while(acc <= fabs(sinval - sinx)); printf("Sum of the sine series = %f\n", sinx); printf("Using Library function sin(%d) = %f\n", x1,sin(x)); } /*End of main() */ /*------------------------------ Output Enter the value of x (in degrees) 30 Enter the accuary for the result 0.000001 Sum of the sine series = 0.500059 Using Library function sin(30) = 0.500059 RUN 2 Enter the value of x (in degrees) 45 Enter the accuary for the result 0.0001 Sum of the sine series = 0.707215 Using Library function sin(45) = 0.707179 ---------------------------------------------*/ ******************************************************************************** 4. /* Write a C program to find the value of cos(x) using the series * * up to the given accuracy (without using user defined function) * * Also print cos(x) using library function. */ #include
#include
#include
main()
{
float acc, term, den, x, cosx=0, cosval;
int i, n, x1;
clrscr();
printf("Enter the value of x (in degrees)\n");
scanf("%f",&x);
x1 = x;
/* Degrees to radians*/
x = x*(3.142/180.0);
cosval = cos(x);
printf("Enter the accuary for the result\n");
scanf("%f", &acc);
term = 1;
cosx = term;
n = 1;
do
{
den = 2*n*(2*n-1);
term = -term * x * x / den;
cosx = cosx + term;
n = n + 1;
} while(acc <= fabs(cosval - cosx)); printf("Sum of the cosine series = %f\n", cosx); printf("Using Library function cos(%d) = %f\n", x1,cos(x)); } /*End of main() */ /*------------------------------ Output Enter the value of x (in degrees) 30 Enter the accuary for the result 0.000001 Sum of the cosine series = 0.865991 Using Library function cos(30) = 0.865991 RUN 2 Enter the value of x (in degrees) 45 Enter the accuary for the result 0.0001 Sum of the cosine series = 0.707031 Using Library function cos(45) = 0.707035 ---------------------------------------------*/ **************************************************************************** 5. /* Write a C program to check whether a given number is prime or not * * and output the given number with suitable message */ #include
#include
main()
{
int num, j, flag;
clrscr();
printf("Enter a number\n");
scanf("%d", &num);
if ( num <= 1)
{
printf("%d is not a prime numbers\n", num);
exit(1);
}
flag = 0;
for ( j=2; j<= num/2; j++)
{
if( ( num % j ) == 0)
{
flag = 1;
break;
}
}
if(flag == 0)
printf("%d is a prime number\n",num);
else
printf("%d is not a prime number\n", num);
}
/*------------------------
Output
RUN 1
Enter a number
34
34 is not a prime number
RUN 2
Enter a number
29
29 is a prime number
-----------------------------*/
C program-3
1. /* Write a C program to find the biggest of three numbers*/
#include
#include
main()
{
int a, b, c;
clrscr();
printf("Enter the values of a,b and c\n");
scanf ("%d %d %d", &a, &b, &c);
printf ("a = %d\tb = %d\tc = %d\n", a,b,c);
if ( a > b)
{
if ( a > c)
{
printf ("A is the greatest among three\n");
}
else
{
printf ("C is the greatest among three\n");
}
}
else if (b > c)
{
printf ("B is the greatest among three\n");
}
else
printf ("C is the greatest among three\n");
}
/*-----------------------------
Output
Enter the values of a,b and c
23 32 45
a = 23 b = 32 c = 45
C is the greatest among three
RUN2
Enter the values of a,b and c
234
678
195
a = 234 b = 678 c = 195
B is the greatest among three
RUN3
Enter the values of a,b and c
30 20 10
a = 30 b = 20 c = 10
A is the greatest among three
------------------------------*/
***************************************************************
2. /* write a C program to find and output all the roots of a *
* quadratic equation, for non-zero coefficients. In case *
* of errors your program should report suitable error message*/
#include
#include
#include
main()
{
float A, B, C, root1, root2;
float realp, imagp, disc;
clrscr();
printf("Enter the values of A, B and C\n");
scanf("%f %f %f", &A,&B,&C);
if( A==0 || B==0 || C==0)
{
printf("Error: Roots cannot be determined\n");
exit(1);
}
else
{
disc = B*B - 4.0*A*C;
if(disc < 0) { printf("Imaginary Roots\n"); realp = -B/(2.0*A) ; imagp = sqrt(abs(disc))/(2.0*A); printf("Root1 = %f +i %f\n",realp, imagp); printf("Root2 = %f -i %f\n",realp, imagp); } else if(disc == 0) { printf("Roots are real and equal\n"); root1 = -B/(2.0*A); root2 = root1; printf("Root1 = %f \n",root1); printf("Root2 = %f \n",root2); } else if(disc > 0 )
{
printf("Roots are real and distinct\n");
root1 =(-B+sqrt(disc))/(2.0*A);
root2 =(-B-sqrt(disc))/(2.0*A);
printf("Root1 = %f \n",root1);
printf("Root2 = %f \n",root2);
}
}
} /* End of main() */
/*---------------------------
Output
RUN 1
Enter the values of A, B and C
3 2 1
Imaginary Roots
Root1 = -0.333333 +i 0.471405
Root2 = -0.333333 -i 0.471405
RUN 2
Enter the values of A, B and C
1 2 1
Roots are real and equal
Root1 = -1.000000
Root2 = -1.000000
RUN 3
Enter the values of A, B and C
3 5 2
Roots are real and distinct
Root1 = -0.666667
Root2 = -1.000000
---------------------------------*/
************************************************************
3. /* Write a C program to simulate a simple calculator to perform *
* arithmetic operations like addition, subtraction,multiplication *
* and division only on integers. Error message should be repoetrd *
* if any attempt is made to divide by zero */
#include
main()
{
char operator;
float n1, n2;
float sum, diff, prod, quot, result;
clrscr();
printf ("Simulation of Simple Calculator\n\n");
printf("Enter two numbers\n");
scanf ("%f %f", &n1, &n2);
fflush (stdin);
printf("Enter the operator [+,-,*,/]\n");
scanf ("%c", &operator);
switch (operator)
{
case '+': result = n1 + n2;
break;
case '-': result = n1 - n2;
break;
case '*': result = n1 * n2;
break;
case '/': result = n1 / n2;
break;
default : printf ("Error in operation\n");
break;
}
printf ("\n%5.2f %c %5.2f= %5.2f\n", n1,operator, n2, result);
}
/*-----------------------------
Output
Simulation of Simple Calculator
Enter two numbers
3 5
Enter the operator [+,-,*,/]
+
3.00 + 5.00= 8.00
RUN2
Simulation of Simple Calculator
Enter two numbers
12.75
8.45
Enter the operator [+,-,*,/]
-
12.75 - 8.45= 4.30
RUN3
Simulation of Simple Calculator
Enter two numbers
12 12
Enter the operator [+,-,*,/]
*
12.00 * 12.00= 144.00
RUN4
Simulation of Simple Calculator
Enter two numbers
5
9
Enter the operator [+,-,*,/]
/
5.00 / 9.00= 0.56
------------------------------*/
**************************************************************************
4. /* Write a C program to simulate a simple calculator to perform *
* arithmetic operations like addition, subtraction,multiplication *
* and division only on integers. Error message should be repoetrd *
* if any attempt is made to divide by zero */
#include
main()
{
char operator;
float n1, n2;
float sum, diff, prod, quot, result;
clrscr();
printf ("Simulation of Simple Calculator\n\n");
printf("Enter two numbers\n");
scanf ("%f %f", &n1, &n2);
fflush (stdin);
printf("Enter the operator [+,-,*,/]\n");
scanf ("%c", &operator);
switch (operator)
{
case '+': result = n1 + n2;
break;
case '-': result = n1 - n2;
break;
case '*': result = n1 * n2;
break;
case '/': result = n1 / n2;
break;
default : printf ("Error in operation\n");
break;
}
printf ("\n%5.2f %c %5.2f= %5.2f\n", n1,operator, n2, result);
}
/*-----------------------------
Output
Simulation of Simple Calculator
Enter two numbers
3 5
Enter the operator [+,-,*,/]
+
3.00 + 5.00= 8.00
RUN2
Simulation of Simple Calculator
Enter two numbers
12.75
8.45
Enter the operator [+,-,*,/]
-
12.75 - 8.45= 4.30
RUN3
Simulation of Simple Calculator
Enter two numbers
12 12
Enter the operator [+,-,*,/]
*
12.00 * 12.00= 144.00
RUN4
Simulation of Simple Calculator
Enter two numbers
5
9
Enter the operator [+,-,*,/]
/
5.00 / 9.00= 0.56
------------------------------*/
***********************************************************************
5. /*Write a C program to generate and print first N FIBONACCI numbers*/
#include
main()
{
int fib1=0, fib2=1, fib3, N, count=0;
printf("Enter the value of N\n");
scanf("%d", &N);
printf("First %d FIBONACCI numbers are ...\n", N);
printf("%d\n",fib1);
printf("%d\n",fib2);
count = 2; /* fib1 and fib2 are already used */
while( count < N) { fib3 = fib1 + fib2; count ++; printf("%d\n",fib3); fib1 = fib2; fib2 = fib3; } } /* End of main() */ /*-------------------------- Enter the value of N 10 First 5 FIBONACCI numbers are ... 0 1 1 2 3 5 8 13 21 34 -------------------------------*/ ******************************************************************** 6. /* Write a C program to find the GCD and LCM of two integers * * output the results along with the given integers. Use Euclids' algorithm*/ #include
main()
{
int num1, num2, gcd, lcm, remainder, numerator, denominator;
clrscr();
printf("Enter two numbers\n");
scanf("%d %d", &num1,&num2);
if (num1 > num2)
{
numerator = num1;
denominator = num2;
}
else
{
numerator = num2;
denominator = num1;
}
remainder = num1 % num2;
while(remainder !=0)
{
numerator = denominator;
denominator = remainder;
remainder = numerator % denominator;
}
gcd = denominator;
lcm = num1 * num2 / gcd;
printf("GCD of %d and %d = %d \n", num1,num2,gcd);
printf("LCM of %d and %d = %d \n", num1,num2,lcm);
} /* End of main() */
/*------------------------
Output
RUN 1
Enter two numbers
5
15
GCD of 5 and 15 = 5
LCM of 5 and 15 = 15
------------------------------*/
********************************************************************************
#include
#include
main()
{
int a, b, c;
clrscr();
printf("Enter the values of a,b and c\n");
scanf ("%d %d %d", &a, &b, &c);
printf ("a = %d\tb = %d\tc = %d\n", a,b,c);
if ( a > b)
{
if ( a > c)
{
printf ("A is the greatest among three\n");
}
else
{
printf ("C is the greatest among three\n");
}
}
else if (b > c)
{
printf ("B is the greatest among three\n");
}
else
printf ("C is the greatest among three\n");
}
/*-----------------------------
Output
Enter the values of a,b and c
23 32 45
a = 23 b = 32 c = 45
C is the greatest among three
RUN2
Enter the values of a,b and c
234
678
195
a = 234 b = 678 c = 195
B is the greatest among three
RUN3
Enter the values of a,b and c
30 20 10
a = 30 b = 20 c = 10
A is the greatest among three
------------------------------*/
***************************************************************
2. /* write a C program to find and output all the roots of a *
* quadratic equation, for non-zero coefficients. In case *
* of errors your program should report suitable error message*/
#include
#include
#include
main()
{
float A, B, C, root1, root2;
float realp, imagp, disc;
clrscr();
printf("Enter the values of A, B and C\n");
scanf("%f %f %f", &A,&B,&C);
if( A==0 || B==0 || C==0)
{
printf("Error: Roots cannot be determined\n");
exit(1);
}
else
{
disc = B*B - 4.0*A*C;
if(disc < 0) { printf("Imaginary Roots\n"); realp = -B/(2.0*A) ; imagp = sqrt(abs(disc))/(2.0*A); printf("Root1 = %f +i %f\n",realp, imagp); printf("Root2 = %f -i %f\n",realp, imagp); } else if(disc == 0) { printf("Roots are real and equal\n"); root1 = -B/(2.0*A); root2 = root1; printf("Root1 = %f \n",root1); printf("Root2 = %f \n",root2); } else if(disc > 0 )
{
printf("Roots are real and distinct\n");
root1 =(-B+sqrt(disc))/(2.0*A);
root2 =(-B-sqrt(disc))/(2.0*A);
printf("Root1 = %f \n",root1);
printf("Root2 = %f \n",root2);
}
}
} /* End of main() */
/*---------------------------
Output
RUN 1
Enter the values of A, B and C
3 2 1
Imaginary Roots
Root1 = -0.333333 +i 0.471405
Root2 = -0.333333 -i 0.471405
RUN 2
Enter the values of A, B and C
1 2 1
Roots are real and equal
Root1 = -1.000000
Root2 = -1.000000
RUN 3
Enter the values of A, B and C
3 5 2
Roots are real and distinct
Root1 = -0.666667
Root2 = -1.000000
---------------------------------*/
************************************************************
3. /* Write a C program to simulate a simple calculator to perform *
* arithmetic operations like addition, subtraction,multiplication *
* and division only on integers. Error message should be repoetrd *
* if any attempt is made to divide by zero */
#include
main()
{
char operator;
float n1, n2;
float sum, diff, prod, quot, result;
clrscr();
printf ("Simulation of Simple Calculator\n\n");
printf("Enter two numbers\n");
scanf ("%f %f", &n1, &n2);
fflush (stdin);
printf("Enter the operator [+,-,*,/]\n");
scanf ("%c", &operator);
switch (operator)
{
case '+': result = n1 + n2;
break;
case '-': result = n1 - n2;
break;
case '*': result = n1 * n2;
break;
case '/': result = n1 / n2;
break;
default : printf ("Error in operation\n");
break;
}
printf ("\n%5.2f %c %5.2f= %5.2f\n", n1,operator, n2, result);
}
/*-----------------------------
Output
Simulation of Simple Calculator
Enter two numbers
3 5
Enter the operator [+,-,*,/]
+
3.00 + 5.00= 8.00
RUN2
Simulation of Simple Calculator
Enter two numbers
12.75
8.45
Enter the operator [+,-,*,/]
-
12.75 - 8.45= 4.30
RUN3
Simulation of Simple Calculator
Enter two numbers
12 12
Enter the operator [+,-,*,/]
*
12.00 * 12.00= 144.00
RUN4
Simulation of Simple Calculator
Enter two numbers
5
9
Enter the operator [+,-,*,/]
/
5.00 / 9.00= 0.56
------------------------------*/
**************************************************************************
4. /* Write a C program to simulate a simple calculator to perform *
* arithmetic operations like addition, subtraction,multiplication *
* and division only on integers. Error message should be repoetrd *
* if any attempt is made to divide by zero */
#include
main()
{
char operator;
float n1, n2;
float sum, diff, prod, quot, result;
clrscr();
printf ("Simulation of Simple Calculator\n\n");
printf("Enter two numbers\n");
scanf ("%f %f", &n1, &n2);
fflush (stdin);
printf("Enter the operator [+,-,*,/]\n");
scanf ("%c", &operator);
switch (operator)
{
case '+': result = n1 + n2;
break;
case '-': result = n1 - n2;
break;
case '*': result = n1 * n2;
break;
case '/': result = n1 / n2;
break;
default : printf ("Error in operation\n");
break;
}
printf ("\n%5.2f %c %5.2f= %5.2f\n", n1,operator, n2, result);
}
/*-----------------------------
Output
Simulation of Simple Calculator
Enter two numbers
3 5
Enter the operator [+,-,*,/]
+
3.00 + 5.00= 8.00
RUN2
Simulation of Simple Calculator
Enter two numbers
12.75
8.45
Enter the operator [+,-,*,/]
-
12.75 - 8.45= 4.30
RUN3
Simulation of Simple Calculator
Enter two numbers
12 12
Enter the operator [+,-,*,/]
*
12.00 * 12.00= 144.00
RUN4
Simulation of Simple Calculator
Enter two numbers
5
9
Enter the operator [+,-,*,/]
/
5.00 / 9.00= 0.56
------------------------------*/
***********************************************************************
5. /*Write a C program to generate and print first N FIBONACCI numbers*/
#include
main()
{
int fib1=0, fib2=1, fib3, N, count=0;
printf("Enter the value of N\n");
scanf("%d", &N);
printf("First %d FIBONACCI numbers are ...\n", N);
printf("%d\n",fib1);
printf("%d\n",fib2);
count = 2; /* fib1 and fib2 are already used */
while( count < N) { fib3 = fib1 + fib2; count ++; printf("%d\n",fib3); fib1 = fib2; fib2 = fib3; } } /* End of main() */ /*-------------------------- Enter the value of N 10 First 5 FIBONACCI numbers are ... 0 1 1 2 3 5 8 13 21 34 -------------------------------*/ ******************************************************************** 6. /* Write a C program to find the GCD and LCM of two integers * * output the results along with the given integers. Use Euclids' algorithm*/ #include
main()
{
int num1, num2, gcd, lcm, remainder, numerator, denominator;
clrscr();
printf("Enter two numbers\n");
scanf("%d %d", &num1,&num2);
if (num1 > num2)
{
numerator = num1;
denominator = num2;
}
else
{
numerator = num2;
denominator = num1;
}
remainder = num1 % num2;
while(remainder !=0)
{
numerator = denominator;
denominator = remainder;
remainder = numerator % denominator;
}
gcd = denominator;
lcm = num1 * num2 / gcd;
printf("GCD of %d and %d = %d \n", num1,num2,gcd);
printf("LCM of %d and %d = %d \n", num1,num2,lcm);
} /* End of main() */
/*------------------------
Output
RUN 1
Enter two numbers
5
15
GCD of 5 and 15 = 5
LCM of 5 and 15 = 15
------------------------------*/
********************************************************************************
C program-2
1 ./* Write a C program to find the area of a triangle, given three sides*/
#include
#include
main()
{
int s, a, b, c, area;
clrscr();
printf("Enter the values of a,b and c\n");
scanf ("%d %d %d", &a, &b, &c);
/* compute s*/
s = (a + b + c) / 2;
area = sqrt ( s * (s-a) * (s-b) * (s-c));
printf ("Area of a triangale = %d\n", area);
}
/*-----------------------------
Output
Enter the values of a,b and c
3
4
5
Area of a triangale = 6
------------------------------*/
**********************************************************************
2. /* Write a C program to find the area of a circl, given the adius*/
#include
#include
#define PI 3.142
main()
{
float radius, area;
clrscr();
printf("Enter the radius of a circle\n");
scanf ("%f", &radius);
area = PI * pow (radius,2);
printf ("Area of a circle = %5.2f\n", area);
}
/*-----------------------------
Output
RUN1
Enter the radius of a circle
3.2
Area of a circle = 32.17
RUN 2
Enter the radius of a circle
6
Area of a circle = 113.11
------------------------------*/
************************************************************************
3. /* Write a C program to find the simple interest , given principle, *
* rate of interest and times*/
#include
main()
{
float p, r, si;
int t;
clrscr();
printf("Enter the values of p,r and t\n");
scanf ("%f %f %d", &p, &r, &t);
si = (p * r * t)/ 100.0;
printf ("Amount = Rs. %5.2f\n", p);
printf ("Rate = Rs. %5.2f%\n", r);
printf ("Time = %d years\n", t);
printf ("Simple interest = %5.2f\n", si);
}
/*-----------------------------
Output
Enter the values of p,r and t
2000
8
3
Amount = Rs. 2000.00
Rate = Rs. 8.00%
Time = 3 years
Simple interest = 480.00
------------------------------*/
*****************************************************************
4. /* Write a C program to check whether a given integer is odd or even*/
#include
main()
{
int ival, remainder;
clrscr();
printf("Enter an integer :");
scanf ("%d", &ival);
remainder = ival % 2;
if (remainder == 0)
printf ("%d, is an even integer\n", ival);
else
printf ("%d, is an odd integer\n", ival);
}
/*-----------------------------
Output
RUN1
Enter an integer :13
13, is an odd integer
RUN2
Enter an integer :24
24, is an even integer
---------------------------------*/
******************************************************************************
5. /* Write a C program to check whether a given integer *
* number is positive or negative*/
#include
main()
{
int number;
clrscr();
printf("Enter a number\n");
scanf ("%d", &number);
if (number > 0)
printf ("%d, is a positive number\n", number);
else
printf ("%d, is a negative number\n", number);
}
/*-----------------------------
Output
Enter a number
-5
-5, is a negative number
RUN2
Enter a number
89
89, is a positive number
------------------------------*/
****************************************************************
#include
#include
main()
{
int s, a, b, c, area;
clrscr();
printf("Enter the values of a,b and c\n");
scanf ("%d %d %d", &a, &b, &c);
/* compute s*/
s = (a + b + c) / 2;
area = sqrt ( s * (s-a) * (s-b) * (s-c));
printf ("Area of a triangale = %d\n", area);
}
/*-----------------------------
Output
Enter the values of a,b and c
3
4
5
Area of a triangale = 6
------------------------------*/
**********************************************************************
2. /* Write a C program to find the area of a circl, given the adius*/
#include
#include
#define PI 3.142
main()
{
float radius, area;
clrscr();
printf("Enter the radius of a circle\n");
scanf ("%f", &radius);
area = PI * pow (radius,2);
printf ("Area of a circle = %5.2f\n", area);
}
/*-----------------------------
Output
RUN1
Enter the radius of a circle
3.2
Area of a circle = 32.17
RUN 2
Enter the radius of a circle
6
Area of a circle = 113.11
------------------------------*/
************************************************************************
3. /* Write a C program to find the simple interest , given principle, *
* rate of interest and times*/
#include
main()
{
float p, r, si;
int t;
clrscr();
printf("Enter the values of p,r and t\n");
scanf ("%f %f %d", &p, &r, &t);
si = (p * r * t)/ 100.0;
printf ("Amount = Rs. %5.2f\n", p);
printf ("Rate = Rs. %5.2f%\n", r);
printf ("Time = %d years\n", t);
printf ("Simple interest = %5.2f\n", si);
}
/*-----------------------------
Output
Enter the values of p,r and t
2000
8
3
Amount = Rs. 2000.00
Rate = Rs. 8.00%
Time = 3 years
Simple interest = 480.00
------------------------------*/
*****************************************************************
4. /* Write a C program to check whether a given integer is odd or even*/
#include
main()
{
int ival, remainder;
clrscr();
printf("Enter an integer :");
scanf ("%d", &ival);
remainder = ival % 2;
if (remainder == 0)
printf ("%d, is an even integer\n", ival);
else
printf ("%d, is an odd integer\n", ival);
}
/*-----------------------------
Output
RUN1
Enter an integer :13
13, is an odd integer
RUN2
Enter an integer :24
24, is an even integer
---------------------------------*/
******************************************************************************
5. /* Write a C program to check whether a given integer *
* number is positive or negative*/
#include
main()
{
int number;
clrscr();
printf("Enter a number\n");
scanf ("%d", &number);
if (number > 0)
printf ("%d, is a positive number\n", number);
else
printf ("%d, is a negative number\n", number);
}
/*-----------------------------
Output
Enter a number
-5
-5, is a negative number
RUN2
Enter a number
89
89, is a positive number
------------------------------*/
****************************************************************
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